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3 years ago

7

PLEASE help quick it is almost due

1 answer:

Dennis_Churaev [7]3 years ago

3 0

Answer:

D.

Step-by-step explanation:

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1.<br> Explain why the diagram shows that 6 (3 + 4) = 6*3 + 6*4

anygoal [31]

Answer:

I'm using algebra format ok so if u get it wrong pls dont kill me. 6(3+4) = 6*3 + 6*4 brackets in algebra means times so 6 times 3 + 6 times 4 done

5 0

4 years ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

7 0

3 years ago

Simplify the expression where possible.(-4 x^2 )^2

Oduvanchick [21]

Answer:

$16x^{4}$

Step-by-step explanation:

$(a^{m})^{n}=a^{m*n} \\\\\\$ and $(a*b)^{m}= a^{m}*b^{m}$

$(-4x^{2})^{2} = (-4)^{2} *(x^{2})^{2}\\\\\\=16 * x^{2*2}\\\\=16x^{4}$

6 0

4 years ago

I have no idea what the heck evaluate means

lord [1]

Evaluate basically just means to solve.

Replace the given vaule of m into the equation to get -8/2.

Then solve.

-8 divided by 2 is -4

8 0

4 years ago

Read 2 more answers

the Earth has an average distance from the Sun of 1.5* 10 to the 8th power kilometers and the Earth has an approximate distance

Aleks04 [339]

Answer:

Earth's average distance from the Sun is $375$ times more than is from the Moon.

Step-by-step explanation:

Given the average distance of Earth from the Sun is $1.5\times10^{8}$ kilometers.

Also, the approximate distance of Earth from the Moon is $4\times10^{5}$ kilometers.

For this, we will divide the average distance of Earth from the Sun by approximate distance of Earth from the Moon.

So,

$\frac{1.5\times10^{8}}{4\times10^{5}}=375\ km$

4 0

3 years ago