Part A)
If f(x) - 3 is the new equation, it means there is a vertical translation of f(x) down 3 units. The y-intercept will decrease by 3 units. Areas of increasing on the function may be lessened as the function is being translated down 3 units. The areas of decrease will increase because the function is being translated down. End behaviour will not change from a translation as long as the function is continuous at each end, (not a finite function with end points). The evenness or oddness of f(x) will not change either.
Part B:
The y-intercept will be flipped horizontally about the x-axis and multiplied by 2. This will mean that if the y-intercept was positive, it will now be negative and vice versa. The increasing and decreasing regions of the graph will be flipped, so anywhere f(x) was positive will now be negative and vice versa. They will also be double what they were before because all values are multiplied by 2. The end behaviour will switch. If f(x) was from Quad1->Quad3 for example, it will now be Quad2->Quad4 because of the flip at the x-axis. The evenness and oddness of the function will not change seeing as the degree of f(x) is not affected.
Use the x and y values from your point and the h and k from the center to write the equation you need to solve for r. The general form of the equation for a circle is
![(x-h) ^{2} +(y-k) ^{2} = r^{2}](https://tex.z-dn.net/?f=%28x-h%29%20%5E%7B2%7D%20%2B%28y-k%29%20%5E%7B2%7D%20%3D%20r%5E%7B2%7D%20)
. We will fill in accordingly:
![(5-3) ^{2}+(4-2) ^{2} = r^{2}](https://tex.z-dn.net/?f=%285-3%29%20%5E%7B2%7D%2B%284-2%29%20%5E%7B2%7D%20%3D%20r%5E%7B2%7D%20)
. Solve for r to get that
It simplifies to -6a^6b^2c^5+2a^2bc^6
Answer:
i think -575
Step-by-step explanation:
A) 21 (21 - 1 = 20)
B) 75 (8 x 15 = 120; 120 - 3 - 10 - 8 - 3 - 10 - 1 - 10 = 75)
C) 6 (any value close to the mean)