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Likurg_2 [28]
3 years ago
9

Please help me with this

Mathematics
2 answers:
fiasKO [112]3 years ago
8 0
You can go on 11 rides
laila [671]3 years ago
3 0

Answer:

sry

Step-by-step explanation:

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A cake with a regular hexagonal top is sliced along each of its 9 diagonals what percent of the resulting 24 pieces are triangle
jeyben [28]
 <span>i guess it means that its a cake with a top shaped like a hexagon. if you were to use paper and cut out a hexagon then fold it, you would find out that it has 9 diagonals(meaning that you are able to fold it equally into 9 pieces). when it is unfolded, you will see 24 pieces and you will have to figure out which of the 24 pieces are triangles and which are not. after that, you calculate the percentage of triangles. 

after you are finished with the paper, you apply the information to the cake. 
i'm not sure if this is right, but you can try it out.</span>
5 0
3 years ago
Read 2 more answers
A mechanic ground 6 valves in 25 minutes. At that rate,
pickupchik [31]

Answer:

3hours and 12.5 minutes

Step-by-step explanation:

45/6=7.5x25=187.5/60=3hours and 12.5 minutes

5 0
3 years ago
1) Which rate is the lowest price?
jeyben [28]
1. 2.5/5 = .50
    2.4/6 = .40 Lowest price
    3.0/6 = .50
    2.4/4 = .60

2. 150/6 = 25 Equivalent
    50/1.5 = 33.33
    100/3.8 = 26.32
    75/3 = 25 Equivalent

3. 30/1 = 30
    90/2 = 45
    180/3 = 60 Fastest
    240/6 = 40

3 0
3 years ago
Pls help fassstttttttt
tamaranim1 [39]

kskskzjsmmsksjsjsjaksnnsns
8 0
2 years ago
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An aircraft carrier made a trip. The trip there took 5 hours and the trip back took 6 hours. It averaged 3 mph faster on the tri
kogti [31]

Answer: The outbound trip is 18 miles per hour

Step-by-step explanation:

Let x represent the speed of the plane.

An aircraft carrier made a trip. Let us assume that this trip was outbound. The trip there took 5 hours.

Distance = speed × time. Therefore

Distance = 5x

The trip back took 6 hours. It averaged 3 mph faster on the trip there then on the return trip. This means that the speed on the trip back is x - 3 mph.

Distance = 6(x-3) = 6x - 18

Since the distance is the same,

5x = 6x - 18

6x - 5x = 18

x = 18

The speed on return or inbound trip would be 18 - 3 = 15 mph

7 0
3 years ago
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