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3 years ago

The surface areas of the two solids shown above are equal. O A. True O B. False

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

4 0

The answer to this question is false

nikdorinn [45]3 years ago

3 0

Answer:

False

Step-by-step explanation:

If we were to flip the solid on the left so its parallel to the solid on the right, we would be able to compare the two more easier.

We can see that the right solid has dimensions of:

L = 1 cm

W = 3 cm

H = 5 cm

The left solid has dimensions of:

L = 1

W = 2

H = 7

If we were to add these all up, they would not equal.

R: 1 + 3 + 5 = 9

L: 1 + 2 + 7 = 10

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#19<br> The distance between the points (4, 1) and (9, 1) is

kirill115 [55]

Hello!

Given the two points, $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ , and to find the distance between these two points is found by using the formula:

$d = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$

$(x_{1}, y_{1})$ is assigned to one the points, in this case, is (4, 1).

$(x_{2}, y_{2})$ is assigned to other point, which is (9, 1).

Then, plug in these values into the formula and solve.

$d = \sqrt{(9-4)^{2}-(1-1)^{2}}$

$d = \sqrt{5^{2}-0^{2}}$

$d = \sqrt{25}$

$d = 5$

Therefore, the distance between the two points is 5.

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3 years ago

Divide using a common factor of 2 to find an equivalent fraction for 2/6

Ludmilka [50]

Answer:

4/12

Step-by-step explanation:

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2 years ago

What is the distance between begin ordered pair 8 comma negative 3 comma 4 end ordered pair and begin ordered pair 6 comma negat

katen-ka-za [31]

Answer:

$d = \sqrt{14} = 3.74...$

Step-by-step explanation:

To find the distance between (8, -3, 4) and (6, -4, 1), use the distance formula for (x,y,z) points. It is very similar to (x,y) points.

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2 - z_1)^2} \\d = \sqrt{(8 - 6)^2 + (-3--4)^2 + (4-1)^2} \\d = \sqrt{(2)^2 + (1)^2 + (3)^2} \\d = \sqrt{4 + 1 + 9}\\ d = \sqrt{14} = 3.74...$

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3 years ago

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joja [24]

Answer:

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Step-by-step explanation:

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3 years ago

What is the conjugate<br> 2/4+3i

kondor19780726 [428]

*) 2/4+3i
2+3i
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3 years ago