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torisob [31]
3 years ago
9

LINKING IN TECHNICAL OBJECTS 1 a) What is linking?

Chemistry
2 answers:
Veronika [31]3 years ago
5 0

Answer:

Linking is the process of combining all the component object files. The linker determines where the code will reside in memory and how control will transfer between the components.

d1i1m1o1n [39]3 years ago
4 0

Answer:

A link is a fastening unit that attaches two parts of an object together

Different types of links have different characteristics

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Determine the amount of heat (in kj) required to vaporize 1.55 kg of water at its boiling point. for water, δhvap
Usimov [2.4K]
Heat required to vaporize 1 mol of water from water at 100C to steam at 100C = 40.7 kJ 
<span>1 mol of water weighs =  18.015g
</span>1.55 kg = <span>1550/18.015 mol = 86.03 mol 

</span><span>Heat required to vaporize :
</span>= 86.03 mol  x <span>40.7 kJ 
</span>
= 3501.421 kJ
5 0
3 years ago
Suppose that some FeSCN2+ is added to the above solution to shift the equilibrium. When equilibrium is re-established, the follo
kiruha [24]

Explanation:

The given reaction equation will be as follows.

          [FeSCN^{2+}] \rightleftharpoons [Fe^{3+}] + [SCN^{-}]

Let is assume that at equilibrium the concentrations of given species are as follows.

        [Fe^{3+}] = 8.17 \times 10^{-3} M

        [SCN^{-}] = 8.60 \times 10^{-3} M

        [FeSCN^{2+}] = 6.25 \times 10^{-2} M

Now, first calculate the value of K_{eq} as follows.

     K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}

              = \frac{8.17 \times 10^{-3} \times 8.60 \times 10^{-3}}{6.25 \times 10^{-2}}

              = 11.24 \times 10^{-4}

Now, according to the concentration values at the re-established equilibrium the value for [FeSCN^{2+}] will be calculated as follows.

             K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}

        11.24 \times 10^{-4} = \frac{8.12 \times 10^{-3} \times 7.84 \times 10^{-3}}{[FeSCN^{2+}]}

         [FeSCN^{2+}] = 5.66 \times 10^{-2} M

Thus, we can conclude that the concentration of [FeSCN^{2+}] in the new equilibrium mixture is 5.66 \times 10^{-2} M.

7 0
3 years ago
Perform the following
Dmitry [639]

Answer:

0.5474

Explanation:

3.22 x 0.17

     \/

322 x 17 = 5,474

[] There are four places "after" the decimal in 3.22 and 0.17 combined, meaning we move the decimal to the right four times in our current answer

-> 5,474 becomes 0.5474

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

4 0
2 years ago
Which biomes would be found nearest to the equator?
lisov135 [29]

Answer:

tropical rain forests and savannas

Explanation:

Tropical rainforests are found near the equator due to the amount of rainfall and the amount of sunshine these areas receive. ...

savannas-Because of their warm climate requirements, savannas tend to be found closer to the equator, which marks the halfway point between the north and south hemispheres of the earth. Because this area gets direct sunlight more of the year than the north and south extremes, the temperature doesn't change much.

8 0
3 years ago
Read 2 more answers
If 12.6 grams of iron (III) oxide reacts with 9.65 grams of carbon monoxide to produce 7.23 g of pure iron, what are the theoret
Mariana [72]
The balanced equation is Fe₂O₃ + 3 CO = 2 Fe + 3 CO₂.
Next step is to convert everything to moles.
12.6g Fe₂O₃ x (1 mol Fe₂O₃ / 159.7g Fe₂O₃) = 0.07890 mol Fe₂O₃ 
9.65g CO x (1 mol CO / 28.01g CO) = 0.3445 mol CO
The third step is to determine the limiting and excess reactants.
0.07890 mol Fe₂O₃ x (3 mol CO/1 mol Fe₂O₃) = 0.2367 mol CO
Therefore Fe₂O₃ is the limiting reagent while CO is in excess.

0.07890 mol Fe x (2 mol Fe(s) / 1 mol Fe₂O₃) = 0.1578 mol Fe(s) 
0.1578 mol Fe x (55.84g Fe / mole Fe) = 8.812g Fe is the theoretical yield
%yield = (7.23g / 8.812g) x 100% = 82.0% is the percent yield
3 0
3 years ago
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