Explanation:
Reversible reactions that happen in a closed system eventually reach equilibrium. At equilibrium, the concentrations of reactants and products do not change. But the forward and reverse reactions have not stopped - they are still going on, and at the same rate as each other.
True
Enzymes help the body in digestion and other bodily functions which involve chemicals.
Answer:
B. CA, 14
Explanation:
Atoms of elements contain small particles known as electrons, neutrons, and protons. The nucleus of an atom is made up of neutrons and protons which are at the center of the atom. Electrons on the other hand surrounds the nucleus. Electron has negative charge while proton has a positive charge. The number of neutrons is equivalent to the number of protons . In addition, the number of protons is equal to mass number minus the number of electrons.
For the compound
, it can be broken down into
and
. Its ion has a mass of 34 and 18 electrons which means it has already lost 2 electrons.
Therefore:
For the given element, the number of electrons is 18+2 = 20 electrons.
The number of protons = 34 - 20 = 14.
And the number of neutrons is 14.
Only option B has the correct answer.
Answer:
0.2007 nm
3.57 cm
0.01478 g
8280000 pg
Explanation:
1)200.7 pm
1 picometer is equal to 0.001 nanometer.
1 nm = 1000 pm
200.7 pm× 1 nm / 1000 pm = 0.2007 nm
2)0.000357 hm
1 hectometer is equal to 10,000 centimeter.
1 hc = 10,000 cm
0.000357 hc× 10,000 cm / 1 hc = 3.57 cm
3) 14.78 mg
1 gram is equal to 1000 milligram.
1 g = 1000 mg
14.78 mg × 1 g/1000 mg = 0.01478 g
4)8.280 µg
1 microgram is equal to 10⁶ picogram.
1 µg = 1000000 pg
8.280 µg× 10⁶ pg/ 1µg = 8.280×10⁶ pg or 8280000 pg
Answer:
0.85 mole of PBr3.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
3Br2 + 2P —> 2PBr3
From the balanced equation above,
3 moles of Br2 reacted to produce 2 moles of PBr3.
Therefore, 1.27 moles of Br2 will react to produce = (1.27 x 2)/ 3 = 0.85 mole of PBr3.
Therefore, 0.85 mole of PBr3 is produced by the reaction.