Answer:
1) HNO3/H2SO4, 2) CH3CH2CH2Cl/AlCl3
Explanation:
Benzene is a stable aromatic compound hence it undergoes substitution rather than addition reaction.
When benzene undergoes substitution reaction, the substituent introduced into the ring determines the position of the incoming electrophile.
If I want to synthesize m-nitropropylbenzene, I will first carry out the nitration of benzene using HNO3/H2SO4 since the -nitro group is a meta director. This is now followed by Friedel Craft's alkykation using CH3CH2CH2Cl/AlCl3.
Answer:
5 significant figures
Explanation:
- Zeros that come before any non-zero digits are never significant.
- Zeros that are in between any non-zero digits are always significant.
- Zeros that come after any non-zero digit are ONLY significant if a decimal point in present somewhere in the number. (In this case there is a decimal point, but there aren't any zeros at the end of this number.)
I have underlined the significant figures in this number:
<u>3</u> <u>8</u> <u>5</u> . <u>0</u> <u>1</u>
All sodium compounds show the same coloured flame because sodium’s familiar bright orange-yellow flame colour results from promoted electrons falling back from the 3p1 level to their normal 3s1 level. The exact sizes of the possible jumps in energy terms vary from one metal to another.
The answer is because like electric charges do not attract with each other. Ions either lack or have excess electrons in their atomic structure. Ions with a positive charge are called cations. They lack electrons in their atoms so they have to pair up with negatively charged ions, called anions, because they have excess electrons. Together, they form a compound that is neutral.
Answer:
SnO2 + 2H2 + energy ➡️ Sn + 2H2O
Explanation