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Drupady [299]
2 years ago
11

5. Why are the poppy seeds placed in different places (not together)?

Chemistry
2 answers:
MAVERICK [17]2 years ago
8 0
In the atom model the poppy seeds are placed in different places to represent the different position of electrons
Mademuasel [1]2 years ago
6 0
In the atom model, the poppy seeds are placed in different places to represent the different position of electrons.
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A gas sample at stp contains 1.15 g oxygen gas and 1.55 g nitrogen gas.what is the volume of the gas sample?
ss7ja [257]
O2=32 g/ mol
1.15/32=0.035
N2=28 g/mol
1.55/28=0.055
in STP every 22.4 litters is 1 mol

4 0
3 years ago
Read 2 more answers
What is 1 mol / 66.04g ​
____ [38]

Answer:

15.142338 mol/kg

Explanation:

(1 mole) / (66.04 grams)

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2 years ago
Egg white, marshmallow, and smoke from a smokestack are examples of _____. suspensions colloids solutions
d1i1m1o1n [39]
They are an example of colloids .....


6 0
2 years ago
What is the source of energy in nuclear power plants?
Zinaida [17]

Answer:

<h2><em><u>URANIUM</u></em><em><u> </u></em></h2>

Explanation:

What is the source of energy in nuclear power plants?

<em><u>Uranium</u></em> is the fuel most widely used by nuclear plants for nuclear fission. <u>Uranium</u> is considered a nonrenewable energy source, even though it is a common metal found in rocks worldwide. Nuclear power plants use a certain kind of uranium, referred to as U-235, for fuel because its atoms are easily split apart.

4 0
1 year ago
The rate constant for a certain reaction is measured at two different temperatures:
Talja [164]

Answer: The activation energy Ea for this reaction is 22689.8 J/mol

Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]

k_1 = rate constant at temperature T_1 = 2.3\times 10^8

k_2 = rate constant at temperature T_2 = 4.8\times 10^8

E_a= activation energy = ?

R= gas constant = 8.314 J/kmol

T_1 = temperature = 280.0^0C=(273+280)=553K

T_2 = temperature = 376.0^0C=(273+376)=649K

Putting in the values ::

ln \frac{4.8\times 10^8}{2.3\times 10^8} = \frac{-E_{a}}{8.314}[\frac{1}{649} - \frac{1}{553}]

E_a=22689.8J/mol

The activation energy Ea for this reaction is 22689.8 J/mol

3 0
2 years ago
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