Question

What is the mass percent of carbon in propanoic acid (C2H5COOH)? (The molar mass of C = 12.01, H = 1.0079, and O = 16.00.)

Answer 1

Mass percent is calculated by the ratio of the mass of the substance in a sample over the total mass of the sample multiplied by 100. Assuming 1 mol of the acid, we will have 74.09 g. We do as follows:

% by mass C = 3 ( 12.01) / 74.09 x 100 = 48.63% C

Answer 2

 The mass percent  of carbon  in propanoic acid is 48.64 % (answer 3)

  calculation

  mass percent = [(mass of carbon  in propanoic  /mass  of   propanoic) x100]

mass  of carbon in propanoic =  (12.01  x2) +  12.01 = 36.03

mass of propanoic =( 12.01 x2) +( 1.0079 x5)  +12.01 +16 +16 + 1.0079 =74.0774

mass percent = 36.03  /74.0774  x 100 = 48.64%