Answer:
If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia
Explanation:
Step 1: Data given
Mass of nitrogen gas (N2) = 13.4 grams
Molar mass of N2 = 28 g/mol
Molar mass of NH3 = 17.03 g/mol
Step 2: The balanced equation
N2 + 3H2 → 2NH3
Step 3: Calculate moles of N2
Moles N2 = Mass N2 / molar mass N2
Moles N2 = 13.4 grams / 28.00 g/mol
Moles N2 = 0.479 moles
Step 4: Calculate moles of NH3
For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3
For 0.479 moles N2 we'll produce 2*0.479 = 0.958 moles
Step 5: Calculate mass of NH3
Mass of NH3 = moles NH3 * molar mass NH3
Mass NH3 = 0.958 moles * 17.03 g/mol
Mass NH3 = 16.3 grams
If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia
Answer:
Explanation:
The acid level has changed
Answer:
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Answer:
A
Explanation:
A catalyst refers to an enzyme composed of peptides in their tertiary conformation.
The addition of a catalyst provides a new path to the reaction and the reaction proceeds in a faster way compared to the reaction without a catalyst.
The peptides are arranged in such a way that they form a pore-like structure which allows the binding of the substrate molecules by forming a temporary covalent bond. These bonds lower the activation energy of the complete reaction which is required to initiate a reaction.
In the given diagram, the activation reaction is represented by the letter "A" and therefore a catalyst will lower and alter the value of A.
Thus, Option-A is correct.
