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vampirchik [111]
3 years ago
10

A longer growing season is a result of

Chemistry
2 answers:
vredina [299]3 years ago
5 0

Answer: <u><em>Hope this helps</em></u>

<u><em /></u>

<h3>Explanation:</h3><h3> <u><em>The growing and flowering seasons of plants will start earlier as a result of an earlier spring caused by warmer conditions. The growing and flowering season will most likely also last longer, resulting in increased plant growth.</em></u></h3><h3><u><em /></u></h3>
Mekhanik [1.2K]3 years ago
3 0

A longer growing season is a result of climate change

Explanation: I hope this help justask me if you need more of an explination

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Suppose the price of gasoline increases 10% and quantity of gasoline demanded in Orlando drops 5% per day. Demand for gasoline i
grin007 [14]

Answer:

The correct answer is;

Demand for gasoline in Orlando is price inelastic.

Explanation:

The elasticity is the degree of response to a change in price or quantity supplied to the the quantity demanded. An elastic demand responds positively to change in price, while an inelastic demand means that when there is a price increase, the quantity demanded remains the same and where there is a drop in price the quantity demanded remains constant.

If a small change in price results in a large change in demand then the good is said to be price elastic

In the question the price increases by 10% while the quantity demanded drops 5 % daily. Therefore it is price inelastic

5 0
3 years ago
Which of these statements is true about heat. 1. Heat always flows from cooler to warmer substances. 2. Heat doesn’t flow betwee
Oksana_A [137]
 heat flows<span> from the </span>warmer<span> body to the </span>cooler<span> body </span>
7 0
3 years ago
Read 2 more answers
Calculate the molality of a 20.0% by mass ammonium sulfate (nh4)2so4 solution. the density of the solution is 1.117 g/ml.
olasank [31]
Hello!

We have the following data:

m1 (solute mass) = 20 % m/m
M1 (Molar mass of solute) (NH4)2 SO4 = ?
m2 (mass of the solvent) = ? (in Kg)

First we find the solute mass (m1), knowing that:

20% m/m = 20g/100mL

20 ------ 100 mL (0,1 L)
y g --------------- 1 L

y = 20/0,1 
y = 200 g --> m1 = 200 g

Let's find Solute's Molar Mass, let's see:

M1 of (Nh4)2SO4
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol

We must find the volume of the solvent and therefore its mass (m2), let us see:

d = 1,117 g/mL
m = 200 g
v (volumen of solute) = ?

d =  \dfrac{m}{V} \to V =  \dfrac{m}{d}

V =  \dfrac{200\:\diagup\!\!\!\!g}{1,117\:\diagup\!\!\!\!g/mL} \to V = 179\:mL\:(volumen\:of\:solute)

<span>The solvent volume will be:
</span>
1000 -179 => V = 821 mL (volumen of disolvent)

If: 1 mL = 1g

<span>Then the mass of the solvent is:
</span>
m2 (mass of the solvent) = 821 g → m2 (mass of the solvent) = 0,821 Kg

Now, we apply all the data found to the formula of Molality, let us see:

\omega =  \dfrac{m_1}{M_1*m_2}

\omega =  \dfrac{200}{132*0,821}

\omega =  \dfrac{200}{108,372}

\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark

_________________________________
_________________________________


<span>Another way to find the answer:
</span>
We have the following data: 

W (molality) = ? (in molal)
n (number of mols) = ?
m1 (solute mass) = 20 % m/m = 20g/100mL → (in g to 1L) = 200 g
m2 (disolvent mass) the remaining percentage, in the case: 80 % m/m = 800 g → m2 (disolvent mass) = 0,8 Kg
M1 (Molar mass of solute) (NH4)2 SO4 
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol 


<span>Let's find the number of mols (n), let's see:

</span>n =  \dfrac{m_1}{M_1}

n = \dfrac{200}{132}

n \approx 1,5\:mol

Now, we apply all the data found to the formula of Molality, let us see:

\omega =  \dfrac{n}{m_2}

\omega =  \dfrac{1,5}{0,8}

&#10;\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark

I hope this helps. =)
7 0
3 years ago
What mass of oxygen is needed for the complete combustion of 4.60×10−3g of methane?
sp2606 [1]
First step in answering the question is to establish a balanced chemical reaction equation. More specifically, a combustion chemical equation. 

CH4 + 2O2 ---> CO2 + 2H20

Then using dimension analysis: 

4.60*10^{-3} g CH4 ( \frac{moleCH4}{16 g CH4}) * ( \frac{2mole O2}{mole CH4}) * ( \frac{32 g O2}{mole O2} ) =  0.0184 g O_{2}
7 0
3 years ago
If an ecosystem element is destroyed, the ecosystem may still be considered sustainable. True False
Andrew [12]
<span>An ecosystem is a complete community of living organisms and the nonliving materials of their surroundings. Thus, its components include plants, animals, and microorganisms; soil, rocks, and minerals; as well as surrounding water sources and the local atmosphere. The size of ecosystems varies tremendously. An ecosystem could be an entire rain forest, covering a geographical area larger than many nations, or it could be a puddle or a backyard garden. Even the body of an animal could be considered an ecosystem, since it is home to numerous microorganisms. On a much larger scale, the history of various human societies provides an instructive illustration as to the ways that ecosystems have influenced civilizations.

</span>
4 0
3 years ago
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