how much heat is absorbed when 15.0 g of liquid water is heated until the temperature increases by 16.0.
1 answer:
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Explanation:
The given data is as follows.
= 0.483,
= 0.173 M,
= 0.433 M,
= 0.306 M,
= 9.0 atm
According to the ideal gas equation, PV = nRT
or, P =
Also, we know that
Density =
So, P = MRT
and, M =
=
=
= 0.368 mol/L
Now, we will calculate the cell potential as follows.
E =
=
=
=
= 0.483 - 0.0185
= 0.4645 V
Thus, we can conclude that the cell potential of given cell at is 0.4645 V.