<span>Orthocenter is at (-3,3)
The orthocenter of a triangle is the intersection of the three heights of the triangle (a line passing through a vertex of the triangle that's perpendicular to the opposite side from the vertex. Those 3 lines should intersect at the same point and that point may be either inside or outside of the triangle. So, let's calculate the 3 lines (we could get by with just 2 of them, but the 3rd line acts as a nice cross check to make certain we didn't do any mistakes.)
Slope XY = (3 - 3)/(-3 - 1) = 0/-4 = 0
Ick. XY is a completely horizontal line and it's perpendicular will be a complete vertical line with a slope of infinity. But that's enough to tell us that the orthocenter will have the same x-coordinate value as vertex Z which is -3.
Slope XZ = (3 - 0)/(-3 - (-3)) = 3/0
Another ick. This slope is completely vertical. So the perpendicular will be complete horizontal with a slope of 0 and will have the same y-coordinate value as vertex Y which is 3.
So the orthocenter is at (-3,3).</span>
No, -4 is not a natural number. It is a negative, the only natural numbers are positiv numbers. Hope this helped!
Answer:
Option (A)
Step-by-step explanation:
The Barnard's Star is usually considered to be a red dwarf, that is approximately six light-years away from the location of earth. It is present in the Ophiuchus constellation and forms the 4th proximate star to the sun.
Altair refers to the bright shining star present in the Aquila constellation. It forms the 12th brightest star that occurs in the night sky.
Spica is one of the proximate stars to the earth and that is extremely large having a mass of almost ten times the mass of the sun.
The mass of Barnard's star is= 2.864 × 10^29 kg
The mass of the Altair is= 3.56 × 10^30 kg
The mass of the Spica= 19.89 × 10^30 kg
The arrangement of these given stars in the increasing order are as follows-
Barnard's star (minimum) < Altair star < Spica star (maximum)
Hence, the correct answer is option (A).
Answer:
Hello I don't know this answer
sorry
