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ZanzabumX [31]
2 years ago
12

Is the incenter always, never, or sometimes inside the triangle

Mathematics
2 answers:
kiruha [24]2 years ago
8 0

Answer:

Always

Step-by-step explanation:

lyudmila [28]2 years ago
5 0

Answer: Always

the incenter is always inside the triangle

Step-by-step explanation:

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If x^(2) - 2 = 2^(2/3) + 2(-2/3) prove that x = 2^(1/3)+2^(-1/3)
dusya [7]

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x² - 2 = 2^(2/3) + 2^(-2/3)

x² = 2^(2/3) + 2 + 2^(-2/3)

x² = (2^(1/3))² + 2 × 2^(1/3) × 2^(-1/3) +

(2^(-1/3))² (It is in the form of a²+2ab+b²)

x² = (2^(1/3) + 2^(-1/3))²

x = 2^(1/3) + 2^(-1/3)

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a shipping clerk must send packages of chemicals to a laboratory. The container she is using to ship the chemicals will hold 18
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6 chemicals

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Given the equation , which set of values for a and
Harrizon [31]

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there is no picture...

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3 0
2 years ago
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Stefan purchases materials to make dog collars. Stefan purchases 10 buckles in a pack and 12 straps in a pack. Stefan doesn't wa
CaHeK987 [17]

Answer:

No

Step-by-step explanation:

Assuming it take 1 buckle and 1 strap per collar, that means we just need to find the lowest common multiple of these 10-pack buckles and 12-pack straps.

For 10: 0, 10, 20, 30, 40, 50, "60", 70, 80, 90, 100...

For 12: 0, 12, 24, 36, 48, "60", 72, 84, 96, 108, 120...

From this, it is obvious that 60 is the lowest common multiple of these two numbers. Therefore, we know that Stefan can make dog collars without having leftover supplies by using 6 10-pack buckles and 5 12-pack straps.

From this, we know that Stefan does not need to buy 120 of either the buckles or the straps.

5 0
3 years ago
HELPPPP<br> please help me answer this question-
erik [133]

Answer:

\displaystyle   GH  =  2 \sqrt{30}

\displaystyle FH = 2 \sqrt{10}

\displaystyle m \angle G =  {30}^{ \circ}

Step-by-step explanation:

<h3>QUESTION-2:</h3>

we are given a right angle triangle

it's a 30-60-90 triangle of which FH is the shortest side

remember that,in case of 30-60-90 triangle the the longest side is twice as much as the shortest side thus

our equation is

\displaystyle 2FH=4\sqrt{10}

divide both sides by 2

\displaystyle\frac{2FH}{2}= \frac{ 4 \sqrt{10} }{2}

\displaystyle FH =2 \sqrt{10}

<h3>Question-1:</h3>

in order to figure out GH we can use Trigonometry because the given triangle is a right angle triangle

as we want to figure out GH we'll use sin function

remember that,

\displaystyle  \sin( \theta)  =  \frac{opp}{hypo}

let our opp, hypo and \theta be GH, 4√10 and 60° respectively

thus substitute:

\displaystyle  \sin(  {60}^{ \circ} )  =  \frac{GH}{4 \sqrt{10} }

recall unit circle:

\displaystyle   \frac{ \sqrt{3} }{2}   =  \frac{GH}{4 \sqrt{10} }

cross multiplication:

\displaystyle   2 GH  =  4 \sqrt{10}  \times  \sqrt{3}

simplify multiplication:

\displaystyle   2 GH  =  4 \sqrt{30}

divide both sides by 2:

\displaystyle   GH  =  2 \sqrt{30}

<h3>QUESTION-3:</h3>

Recall that, the sum of the interior angles of a triangle is 180°

therefore,

\displaystyle m \angle G +  {60}^{ \circ}  + {90}^{ \circ}  =  {180}^{ \circ}

simplify addition:

\displaystyle m \angle G +  {150}^{ \circ}  =  {180}^{ \circ}

cancel 150° from both sides

\displaystyle m \angle G =  {30}^{ \circ}

6 0
3 years ago
Read 2 more answers
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