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sesenic [268]
3 years ago
7

Which chemical equation is balanced? Question 4 options: CH4 + O2 → H2O + CO2 CH4 + O2 → 2H2O + CO2 6CH4 + O2 → 2H2O + 2CO2 CH4

+ 2O2 →2H2O + CO2
WILL GIVE BRAINLIEST
Chemistry
2 answers:
kolbaska11 [484]3 years ago
8 0
Ch4+202-:co2+2H2O
I think so it will be ok
Alexxx [7]3 years ago
6 0

Answer:

CH4 + 2O2 → CO2 + 2H2O

Explanation: Hope this helps you.

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Select the correct answer.
lorasvet [3.4K]

Answer:

D. the energy release increases the molecular motion but decreases the kinetic

energy of the substance

5 0
3 years ago
How much 3.0 M NaOH is needed to neutralize 30. mL of 0.75 M H2SO4?
Nikitich [7]

Answer:

15.0 mL

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

3 0
3 years ago
A compound has an empirical formula of CH2 and a molar mass of 56 g. What is its molecular formula?
kipiarov [429]

Answer:

C4H8

Explanation:

First find the molar mass of CH2;

2(1.01) + 1(12.01) = 14.03g

Now divide the molar mass of the compound by the molar mass of CH2;

56g/14.03g = 3.9914 Round to nearest whole number = 4

Multiply CH2 by 4 to get the molecular formula;

CH2* 4 = C4H8

4 0
3 years ago
The following charges on individual oil droplets were obtained during an experiment similar to Millikan's. Determine a charge fo
RSB [31]

Answer:

- 1.602 x 10⁻¹⁹coulombs

Explanation:

Charge on individual oil droplet would be multiple of charge on one electron . So we will find out the minimum common factor of given individual charges that is the LCM of all the charges given.

LCM of given charges like 3.204 , 4.806 ,8.01 and 14.42 . We have neglected the power of ten( 10⁻¹⁹)  because it is  already a common factor to all.

The LCM  is 1.602 . So charge on electron is 1.602 x 10⁻¹⁹.

4 0
3 years ago
The following equilibrium is formed when copper and bromide ions are placed in a solution:
JulsSmile [24]

Answer:

A)

1. Reaction will shift rightwards towards the products.

2. It will turn green.

3. The solution will be cooler..

B) It will turn green.

Explanation:

Hello,

In this case, for the stated equilibrium:

heat + Cu(H_2O)_6 ^{+2} (blue) + 4Br^- \rightleftharpoons 6H_2O + CuBr_4^{-2} (green)

In such a way, by thinking out the Le Chatelier's principle, we can answer to each question:

A)

1. If potassium bromide, which adds bromide ions, is added more reactant is being added to the solution, therefore, the reaction will shift rightwards towards the products.

2. The formation of the green complex is favored, therefore, it will turn green.

3. The solution will be cooler as heat is converted into "cold" in order to reestablish equilibrium.

B) In this case, as the heat is a reactant, if more heat is added, more products will be formed, which implies that it will turn green.

Regards.

3 0
3 years ago
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