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Bumek [7]
3 years ago
11

How to balance N2O5 +H2O --->HNO3

Chemistry
1 answer:
professor190 [17]3 years ago
8 0
To balance the chemical reaction above, we need to remember that the amount of the elements in the reactant side should be equal to the amount of that element in the product side. The balanced chemical reaction is written as:

<span>N2O5 +H2O --->2HNO3</span>
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Water carries helpful nutrients to new areas,
den301095 [7]

Answer:

Positive Flood I believe

8 0
3 years ago
Read 2 more answers
If the pressure changes from 1 atm to 3 atm, what does the volume of 30 L change to
DiKsa [7]

Answer: 10L

Explanation:

Given that:

Initial pressure P1 = 1 atm

New pressure P2 = 3 atm

Initial volume V2 = 30 L

New volume V2 = ?

Since pressure and volume are involved, apply the formula for Boyle's law

P1V1 = P2V2

1 atm x 30L = 3 atm x V2

30 atm L = 3 atm x V2

V2 = (30 atm L / 3 atm)

V2 = 10L

Thus, volume changed to 10 liters

5 0
2 years ago
Some people must eat a low-sodium diet with no more than 2,000 mg of sodium per day. By eating 1 cracker, 1 pretzel, and 1 cooki
Leni [432]

Answer:

The amount of sodium is 32 mg per cracker, 49 mg per pretzel and 68 mg per cookie.

Explanation:

Let's assume amount of sodium is x mg per cracker, y mg per pretzel and z mg per cookie.

So, the following three equations can be written as per given information:

x+y+z = 149 ........(1)

8y+8z = 936 ........(2)

6x+7y = 535 .........(3)

From equation- (2), y+z = \frac{936}{8} = 117

By substituting the value of (y+z) in equation- (1) we get,

                          x = 149-(y+z) = 149-117 = 32

By substituting the value of x into equation- (3) we get,

                           y = \frac{535-(6\times 32)}{7} = 49

By substituting the value of y  into equation- (2) we get,

                           z = (117-49) = 68

So, the amount of sodium is 32 mg per cracker, 49 mg per pretzel and 68 mg per cookie.

6 0
3 years ago
A sample of granite contains various oxides of silicon, aluminum, sodium, potassium, calcium, and iron. each of these oxides giv
Julli [10]
It would have a solubility substance and surface

4 0
3 years ago
Which of these solutions are basic at 25 °C? Solution A: [OH−]=3.13×10−7 M Solution C: [H3O+]=0.000747 M Solution B: [H3O+
solong [7]

Answer:

Are basic:

[OH⁻] = 3.13x10⁻⁷M and [H₃O⁺] = 9.55x10⁻⁹M

Explanation:

A solution is basic when pH = - log [H₃O⁺] is higher than 7.

It is possible to convert [OH⁻] to [H₃O⁺] using:

[H₃O⁺] = 1x10⁻¹⁴ / [OH⁻]

a. [OH⁻] = 3.13x10⁻⁷M

[H₃O⁺] = 1x10⁻¹⁴ / [3.13x10⁻⁷M]

[H₃O⁺] = 3.19x10⁻⁸M

pH = - log [H₃O⁺] = 7.50

[OH⁻] = 3.13x10⁻⁷M is basic

b. pH = -log [H₃O⁺] = - log 0.000747M = 3.13.

This solution is not basic

c. [H₃O⁺] = 9.55x10⁻⁹M

pH = 8.02

This solution is also basic.

8 0
2 years ago
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