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3 years ago

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You have measured the systolic blood pressure of a random sample of 25 employees of a company located near you. A 95% confidence

interval for the menu systolic blood pressure for the employees of this company is (122, 138). Which of the following statements gives a valid interpretation of the confidence level?a. 95% of the sample of employees have a systolic blood pressure between 122 and 138.b. 95% of tire population of employees have a systolic blood pressure between 122 and 138c. If the procedure were repeated many times, 95% of the resulting confidence intervals would contain the population means systolic blood pressure.d. The probability that the population mean blood pressure is between 122 and 138 is .95

1 answer:

kumpel [21]3 years ago

8 0

I have 0 idea sorry

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Answer: a)

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40 shirts | 349 + 40(4.8)

60 shirts | 349 + 60(4.8)

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Answer:

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And replacing we got:

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And replacing we got:

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And the variance would be:

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And the deviation:

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Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

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And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

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4 years ago

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sammy [17]

Answer:

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$as \: we \: know \: (f.g)x \: is \: same \: as$

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$therefore$

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a_sh-v [17]

I’m pretty sure the answer is C. I’m not entirely sure.

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Answer:

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