All categories

3 years ago

Damon can flip 5 pancakes in 20 seconds,

Mathematics

2 answers:

katen-ka-za [31]3 years ago

7 0

Answer:

24 + 30 = 54 pancakes flipped in 2 minutes :)

Step-by-step explanation:

damon = 5 pancakes in 20 seconds

we do 20 x 3 and 5 x 3 to find how many pancakes he can flip in a minute

15 pancakes and a minute, we then multiply them by 2 to get the amount for 2 minutes

30 pancakes flipped in 2 minutes

Hailey = 2 pancakes in 10 seconds. to make it an equal amount of pancakes per second with damon, i will multiply them by 2 to have 4 pancakes in 20 seconds

we will then do 4 x 3 and 20 x 3 to find out how many pancakes per minute

then we multiply by 2 for 2 minutes

lawyer [7]3 years ago

7 0

Answer:

Step-by-step explanation:

2 minutes=120 seconds

Damon=120 divide 20=6

6x5=30

Hailey=120 divide 10=12

12x2=24

24+30=54

Hope this helps! Thanks.

You might be interested in

WILL GIVE BRAINLIEST if you show your work

KATRIN_1 [288]

Answer:

��

Step-by-step explanation:

��

5 0

2 years ago

Read 2 more answers

TWO MINUTES HURRY HELP ME PLEASE

Elis [28]

Answer:

x=-1

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The sum of three consecutive odd integers is 69. find the integers

Marta_Voda [28]

Let the integers be x-2, x, x+2.

Given,

x -2 + x + x + 2 = 69

3x = 69

x = 23

Hence, the integers are 21, 23 and 25.

6 0

3 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

4 years ago

By what number should ( -5)(-1) be multiplied so that the product may be equal to (10)(-1)

Rudik [331]

Answer: -2

(-5)(-1)x=(10)(-1)
5x = -10
x = -2

7 0

2 years ago