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3 years ago

4. Find the percent of increase or decrease

Mathematics

1 answer:

Vaselesa [24]3 years ago

6 0

Answer:

$2.25 \div 3.5 \times 100 = 65.7percent$

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Subtract the equations.

Lostsunrise [7]

Answer:

0x+2y=22

Step-by-step explanation:

Set them equal to each other, (5x+4y=25)-(5x+2y=3). Distribute the negative into the right equation, (5x+4y=25)(-5x-2y=-3). Then combine like terms to get your answer.

6 0

3 years ago

The McCarter family is determining whether they want to buy a summer pass to the local swimming pool. Without a summer pass, the

Rus_ich [418]

Answer:

D. The McCarter's must make more than 10 visits to the pool for the pass to be a better deal.

Step-by-step explanation:

First, I chose the option that seemed most likely. Once I chose D, I plugged in the answer to see if it actually worked.

10 x 7.5 =75 dollars + 50 (pass fee) = 125 dollars total.

10 x 12.5= 125 dollars.

Therefore, in order to get a deal off of the seasonal pass, the McCarter's would have to visit the pool more than 10 times. D.

8 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

In basketball, Katrina makes 6 out of every 9 free throws. Her coach claims that if she tries 15 free throws she should make 10

zloy xaker [14]

Yes, Thats 2/3 rds of the equation

5 0

3 years ago

Read 2 more answers

Find each measurement. Assume that each figure is not drawn to scale.

ivanzaharov [21]

Answer:

1) 2 1/4 inches (2.25)

2) 5.3 millimeters

3) X=10 and YZ=60

Step-by-step explanation:

Number 1, you just add the measurements because n and q is the start and end of the line segment.

Number 2, you are given the whole measurement, and you know FG which is 9.7, so you subtract the 15 (whole measurement) by 9.7, which is 5.3.

Number 3, you know that XY and YZ equal XZ, so 8x+1 would equal 81. Do the math, you would get 8x=80 and then x=8. Now you know x, plug it in for 6x, so 6(10)=60.

4 0

3 years ago