Answer:
Explanation:
we know that specific heat is the amount of heat required to raise the temperature of substance by one degree mathmeticaly
Q=mcΔT
ΔT=T2-T1
ΔT=26.8-10.2=16.6
C for water is 4.184
therefore
Q=1.00*4.184*16.6
Q=69.4 j
now we have to covert joule into calorie
1 calorie =4.2 j
x calorie=69.4 j/2
so 69.4 j =34.7 calorie thats why 34.7 calorie heat is required to raise the temperature of water from 10.2 to 26.8 degree celsius
Answer:
C6H12O6 —> 2C2H5OH + 2CO2
Explanation:
The equation for the reaction is given below:
C6H12O6 —> C2H5OH + CO2
We can balance the equation above as follow:
There are 12 atoms of H on the left side and 6 atoms of the right side. It can be balance by putting 2 in front of C2H5OH as shown below:
C6H12O6 —> 2C2H5OH + CO2
There are 6 atoms of C on the left side and 5 atoms on the right side. It can be balance by putting 2 in front of CO2 as shown below:
C6H12O6 —> 2C2H5OH + 2CO2
Now the equation is balanced.
Answer:
Favorite Answer
1.0 x10^-14 = (1.0 x 10^-13) (x)
x = 1.0 x 10^-1 = 0.1 M (this is the [OH-])
pOH = -log 0.1 = 1.0
Explanation:
I hope this helps :) sorry if not :(
Molarity = moles of solute(HCl)
------------------------------------
volume of the solution
= 1
------
5
= 0.2M.
Hence option B is correct.
Hope this helps!!
Answer:
613 mg
Explanation:
Number of fargday's 
Here, I = 9.20 A
t = 10.5 min
= 10.5 x 60 seconds
So, 
= 0.0208 F
Here, 2e, 2F
2F = 1 mol of Ni
1 mol = 59 gm of Ni
0.0104 mol = 59 x0.0104 gm Ni
= 0.613 gm Ni
= (0.613 x 1000 ) mg of Ni
= 613 mg of Ni
