What propelled the popper into the air
1 answer:
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So this is the info that's given to us:
m1 = 4.87 x 10^24 kg
m2 = 4.87 x 10^24kg
F = 2.58 x 10^3 N
Now we can use this equation to solve:
You may be asking what g is. Well, it is equal to 6.67x10^-11 m3 /kg s2. G is gravitational constant. So :
As you can see we only have one variable, so we solve for r!
I hope this helps you out. I remember when I was first learning Newton's law<span> of universal </span><span>gravitation and I had some trouble. But with some practice, I got better. =) </span>
m1 = 4.87 x 10^24 kg
m2 = 4.87 x 10^24kg
F = 2.58 x 10^3 N
Now we can use this equation to solve:
You may be asking what g is. Well, it is equal to 6.67x10^-11 m3 /kg s2. G is gravitational constant. So :
As you can see we only have one variable, so we solve for r!
I hope this helps you out. I remember when I was first learning Newton's law<span> of universal </span><span>gravitation and I had some trouble. But with some practice, I got better. =) </span>
The magnitude of the electric force between two obejcts with charge 
and 
is given by Coulomb's law:
where
is the Coulomb's constant
and r is the distance between the two objects.
In our problem, the distance is
, while the magnitudes of the two charges are
(we can neglect the sign of the second charge, since we are interested only in the magnitude of the force).
So, using the formula and the data of the problem, we find
where
and r is the distance between the two objects.
In our problem, the distance is
(we can neglect the sign of the second charge, since we are interested only in the magnitude of the force).
So, using the formula and the data of the problem, we find