Answer:
The number of teenagers in the stratified sample of equal proportion is 30 teenagers
Step-by-step explanation:
Whereby tickets are sold to only adults male and female and teenagers, boys and girls, we have the following groups
Group 1: Female adult
Group 2: Male adult
Group 3: Teenage boys
Group 4: Teenage girls
In stratified sampling, the types of people that visit the zoo (which is the target population) are identified and the appropriate proportion of each of the identified types is determined such that the sample is representative of the population
Where equal number of each group are observed to have visited the zoo, then, the appropriate sample size of the teenager is found as follows;
Number of groups identified = 4
Sample size = 30
Appropriate proportion of each group = 1/4
Number of teenage boys in the sample = 1/4×30 = 15
Number of teenage girls in the sample = 1/4×30 = 15
Total number of teenagers in the sample = 15 + 15 = 30 teenagers.
Answer:
f(-6) = -14
Step-by-step explanation:

Hope this helps you.
Answer:
Fixed expenses = 1767.07
Step-by-step explanation:
Andre calculated his variable and total expenses for last month.
His variable expenses is $2,863.09
His total expenses is $4,630.16
Now, Total expenses = Variable expenses + Fixed expenses
So, Fixed expenses = Total expenses - Variable expenses
⇒ F = T - V
⇒ F = 4630.16 - 2863.09
⇒ F = 1767.07
So, this the equation to represent Andre's fixed income. (Answer)
The flat fee that the store charges is $14 and the cost for 7 hours is $56
A linear equation is on the form:
y = mx + b
where y, x are variables, m is the rate of change and b is the initial value of y.
let f for the total rental cost of a vacuum cleaner for x hours
Using the points (1, 20) and (3, 32) from the table:

The flat fee that the store charges is $14
The reasonable domain is 1 ≤ x ≤ 12
The cost for 7 hours is:
f(7) = 6(7) + 14 = 46
Find out more on linear equation at: brainly.com/question/14323743
Answer: "
x = 1 + √5 " or "
x = 1 − √5" .
______________________________________________________Given:
______________________________________________________ " x² − 2x − <span>4 = 0 " ;
______________________________________________Solve for "x" by using the "quadratic formula" :
</span>Note: This equation is already written in "quadratic format" ; that is:
" ax² + bx + c = 0 " ; { "a

0" } ;
in which: "a = 1" {the implied coefficient of "1" ;
since "1", multiplied by any value, equals that same value};
"b = -2 " ;
"c = -4 " ;
_______________________________________________________The quadratic equation formula:
x = { - b ± √(b² − 4 ac) } / 2a ; {"a

0"} ;
______________________________________________________Substitute our known values:
______________________________________________________ → x = { - (-2) ± √[(-2)² − 4(1)(-4)] } / 2(1) ;
→ x = { 2 ± √(4 − 4(-4) } / 2 ;
→ x = { 2 ± √(4 − (-16) } / 2 ;
→ x = { 2 ± √(4 + 16) } / 2 ;
→ x = { 2 ± √(20) } / 2 ;
→ x = { 2 ± √4 √5} / 2 ;
→ x = { 2 ± 2√5} / 2 ;
→ x = 1 ± √
5 ;
_______________________________________________________→ "
x = 1 + √
5"
or "
x = 1 −
√
5"
.
_______________________________________________________