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IgorLugansk [536]
3 years ago
5

A tank of nitrogen has a volume of 14.0 L and a pressure of 1 atm. Find the volume of the nitrogen when its pressure is changed

to 0.8 atm while the temperature is held constant .
Chemistry
1 answer:
ANEK [815]3 years ago
7 0

Answer:

17.5 L

Explanation:

Step 1: Given data

  • Initial volume of the tank of nitrogen (V₁): 14.0 L
  • Initial pressure of nitrogen (P₁): 1 atm
  • Final volume of the tank of nitrogen (V₂): ?
  • Final pressure of nitrogen (P₂): 0.8 atm

Step 2: Calculate the final volume of the nitrogen

We have a gas that undergoes a change at a constant temperature. If we assume an ideal behavior, we can calculate the final volume of the nitrogen using  Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 1 atm × 14.0 L/0.8 atm = 17.5 L

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3 years ago
Hydrogen is 99% 1H, 0.8% 2H, and 0.2% 3H. Calculate its average atomic mass.
AlekseyPX

The average atomic mass of hydrogen (99% H-1, 0.8% H-2, and 0.2% H-3) is 1.012 amu.    

The average atomic mass of hydrogen can be calculated with the following equation:

A = m_{H-1}\%_{H-1} + m_{H-2}\%_{H-2} + m_{H-3}\%_{H-3}

Where:

m_{H-1}: is the mass of protium (H-1) = 1

m_{H-2}: is the <em>mass</em> of deuterium (H-2) = 2

m_{H-3}: is the <em>mass </em>of tritium (H-3) = 3

\%_{H-1}: is the abundance percent of H-1 = 99%

\%_{H-2}: is the <em>abundance percent</em> of H-2 = 0.8%

\%_{H-3}: is the <em>abundance percent</em> of H-3 = 0.2%

The average atomic mass is:

A = 1*99\% + 2*0.8\% + 3*0.2\%

Changing all the <u>percent values</u> into <u>decimal ones</u>, we have:

A = 0.99 + 2*0.008 + 3*0.002 = 1.012

Therefore, the average atomic mass of hydrogen is 1.012 amu.

Learn more about average atomic mass here brainly.com/question/8575403?referrer=searchResults

I hope it helps you!

6 0
2 years ago
How many grams of a solution that is 50% by weight NaOH
kkurt [141]

Answer:

12 g

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We want to prepare 1 L of a 0.15 M NaOH solution. The moles of NaOH required are:

0.15 mol/L × 1 L = 0.15 mol

The molar mass of NaOH is 40.00 g/mol. The mass corresponding to 0.15 mol is:

0.15 mol × (40.00 g/mol) = 6.0 g

The starting solution is 50% by weight. The mass of solution that contains 6.0 g of NaOH is:

6.0 g NaOH × (100 g solution/50 g NaOH) = 12 g solution

8 0
4 years ago
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