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Leto [7]
3 years ago
5

Given the balanced equation:

Chemistry
1 answer:
Liula [17]3 years ago
8 0

Answer:

In our case, the equation  2KI + F2 → 2 KI + I2 is a single-replacement (also called single- displacement) reaction.

Explanation:

<u>Step 1:</u> The balanced equation:

2KI + F2 → 2 KI + I2

<u>Step 2</u>: What kind of reaction

Since we start with 2 reactants and end with 2 products, we can say it won't be a synthesis or decomposition reaction.

In our case, It looks like it's a replacement reaction.

- A single-replacement reaction is a reaction in which one element replaces a similar element in a compound. The general form of a single-replacement reaction is:  A+BC→AC+B

where element  A  is a metal and replaces element  B , also a metal, in the compound.

When the element that is doing the replacing is a nonmetal, it must replace another nonmetal in a compound.

- A double-replacement reaction is a reaction in which the positive and negative ions of two ionic compounds exchange places to form two new compounds. The general form of a double-replacement reaction is:  AB+CD→AD+BC

In our case, the equation  2KI + F2 → 2 KI + I2 is a <u><em>single-replacement</em></u> (also called single- displacement) reaction.

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3 years ago
4. At what temperature will 1.21 mol of oxygen (O2), exert a pressure of 1862 mmHg in a
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7 0
2 years ago
The half life for the decay of carbon- is years. Suppose the activity due to the radioactive decay of the carbon- in a tiny samp
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Answer:

The artifact is 570 years old. That is, 5.7 × 10² years.

Explanation:

Radioactive decay follows first order reaction kinetics.

Let the initial activity for fresh Carbon-14 be A₀

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The rate of radioactive decay is given by

dA/dt = - KA

dA/A = - kdt

Integrating the left hand side from A₀ to A₀/2 and the right hand side from 0 to t(1/2) (where t(1/2) is the radioactive isotope's half life)

In [(A₀/2)/A₀] = - k t(1/2)

In (1/2) = - k t(1/2)

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t(1/2) is given in the question to be 5.73 × 10³ years

k = (In 2)/5730 = 0.000121 /year

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Integrating the left hand side from A₀ to A and the right hand side from 0 to t

In (A/A₀) = - kt

A/A₀ = e⁻ᵏᵗ

A = A₀ e⁻ᵏᵗ

A = 2.8 × 10³ Bq.

A₀ = 3.0 × 10³ Bq.

2.8 × 10³ = 3.0 × 10³ e⁻ᵏᵗ

0.9333 = e⁻ᵏᵗ

e⁻ᵏᵗ = 0.9333

-kt = In 0.9333

- kt = - 0.06899

t = 0.06899/0.000121 = 570.2 years = 5.7 × 10² years

8 0
2 years ago
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Answer:

C. Work and time

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7 0
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