Draw the condensed structural formulas for all the possible haloalkane isomers that have four carbon atoms and a bromine.
1 answer:
<u>Answer:</u> The isomers are shown in the image below.
<u>Explanation:</u>
Isomers are defined as the chemical compounds having the same number and kinds of atoms but arrangement are different.
For the alkane having four carbon atoms and 1 bromine atom, the IUPAC name of the haloalkane is bromobutane
There are 4 possible isomers for the given haloalkane compound:
- 1-bromobutane
- 2-bromobutane
- 1-bromo-2-methylpropane
- 2-bromo-2-methylpropane
The isomers of the given organic compound is shown in the image below.
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Answer:
The Prandtl number for this example is 14,553.
Explanation:
The Prandlt number is defined as:
To compute the Prandlt number for this case, is best if we use the same units in every term of the formula.
Now that we have coherent units, we can calculate Pr