Answer:
Percentage composition of oxygen = 29.69%
Percentage composition of fluorine = 70.37
Explanation:
Given:
Mass of compound = 0.432 grams
Mass of oxygen = 0.128 grams
Find:
Percentage composition of oxygen
Percentage composition of fluorine
Computation:
Percentage composition of oxygen = [0.128/0.432]100
Percentage composition of oxygen = 29.69%
Percentage composition of fluorine = [(0.432 - 0.128)/0.432]100
Percentage composition of fluorine = 70.37
Q = mCpΔT
Cp = 2.22 J/g°C
m = 150 g
ΔT = T(final) - T(initial) = -15°C - (-30°C) = +15°C
q = (150 g)(2.22 J/g°C)(15°C) = 4,995 J