C) They each form similar compounds when combined with oxygen.
Explanation:
The given elements have a common characteristics as they each form similar compounds when combined with oxygen.
Beryllium, magnesium and calcium all are located in the alkaline earth group.
Elements in the same group have the same chemical properties.
- Density and melting point are physical properties of matter which varies down a group on the periodic table.
- Their reaction with oxygen denotes a statement of their chemical properties.
- Chemical properties of matter is a function of their valency.
- Group two elements have a valency of two. They have two electrons in their outermost shell.
- Therefore, they all form ionic bonds when they react with oxygen.
learn more:
Periodic table brainly.com/question/2690837
#learnwithBrainly
This may seem confusing because they give you two masses, but all you have to do is pick one to do the calculations. Personally, I would pick O2, since the molar mass is easier to calculate. The answer would be 3.3 g (rounded for sig figs). To get this, first take the 5.9 grams of O2 and convert it to moles by dividing by the molar mass of oxygen gas, which is 32. Then, multiply both by the mole-mole ratio, which is 2:2, or simply 1:1. After that, multiply that by 18g, which is the molar mass of water to get grams of water.
REMEMBER, you have to write and balance the chemical equation before you can do any of that work.
That happens to be CH4 + 2O2 => CO2 + 2H2O
I would say that it would be excessive rain and heat. Because, after a drought and a flood happen, standing water is home to mosquitos which carry malaria. I hope this helps!
Explanation:
Reaction equation is as follows.
Here, 1 mole of 
produces 2 moles of cations.
![[Na^{+}] = 2[Na_{2}SO_{3}] = 2 \times 0.58](https://tex.z-dn.net/?f=%5BNa%5E%7B%2B%7D%5D%20%3D%202%5BNa_%7B2%7DSO_%7B3%7D%5D%20%3D%202%20%5Ctimes%200.58)
= 1.16 M
![[SO^{2-}_{3}] = [Na_{2}SO_{3}]](https://tex.z-dn.net/?f=%5BSO%5E%7B2-%7D_%7B3%7D%5D%20%3D%20%5BNa_%7B2%7DSO_%7B3%7D%5D)
= 0.58 M
The sulphite anion will act as a base and react with 
to form 
and 
.
As, 
= 
= 
According to the ICE table for the given reaction,
Initial: 0.58 0 0
Change: -x +x +x
Equilibrium: 0.58 - x x x
So,
![K_{b} = \frac{[HSO^{-}_{3}][OH^{-}]}{[SO^{2-}_{3}]}](https://tex.z-dn.net/?f=K_%7Bb%7D%20%3D%20%5Cfrac%7B%5BHSO%5E%7B-%7D_%7B3%7D%5D%5BOH%5E%7B-%7D%5D%7D%7B%5BSO%5E%7B2-%7D_%7B3%7D%5D%7D)
x = 0.0003 M
So, x = ![[HSO^{-}_{3}] = [OH^{-}]](https://tex.z-dn.net/?f=%5BHSO%5E%7B-%7D_%7B3%7D%5D%20%3D%20%5BOH%5E%7B-%7D%5D)
= 0.0003 M
![[SO^{2-}_{3}]](https://tex.z-dn.net/?f=%5BSO%5E%7B2-%7D_%7B3%7D%5D)
= 0.58 - 0.0003
= 0.579 M
Now, we will use ![[HSO^{-}_{3}]](https://tex.z-dn.net/?f=%5BHSO%5E%7B-%7D_%7B3%7D%5D)
= 0.0003 M
The reaction will be as follows.
Initial: 0.0003
Equilibrium: 0.0003 - x x x
= 
= 
Therefore, 
As, x <<<< 0.0003. So, we can neglect x.
Therefore, 
= 
x = 
x = ![[OH^{-}] = [H_{2}SO_{3}]](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%20%3D%20%5BH_%7B2%7DSO_%7B3%7D%5D)
= 
![[H^{+}] = \frac{10^{-14}}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B10%5E%7B-14%7D%7D%7B%5BOH%5E%7B-%7D%5D%7D)
= 
= 
M
Thus, we can conclude that the concentration of spectator ion is M.
