A 3.1 L sample of hydrogen <u>d. contains the same number of molecules</u>
as 3.1 L of carbon dioxide at the same temperature and pressure.
This is the fundamental principle of <em>Avogadro’s hypothesis</em>: equal volume of gases at the same temperature and pressure contain the same number of molecules.
The sample of carbon dioxide has a <em>greater mass</em>, a <em>greater number of atoms</em>, and a <em>greater density</em>, than the sample of hydrogen.
This question comes with four answer choices:
<span>A. H2O + H2O ⇄ 2H2 + O2
B. H2O + H2O⇄ H2O2 + H2
C. H2O + H2O ⇄ 4H+ + 2O2-
D. H2O + H2O ⇄ H3O+ + OH-
Answer: option </span><span>D. H2O + H2O ⇄ H3O+ + OH-
(the +sign next to H3O is a superscript, as well as the - sing next to OH)
Explanation:
The self-ionization of water, or autodissociation, produces the two ions H3O(+) and OH(-). The presence of ions is what explain the electrical conductivity of pure water.
</span><span>In this, one molecule of H2O loses a proton (H+) (deprotonates) to become a hydroxide ion, OH−. Then, he <span>hydrogen ion, H+</span>, immediately protonates another water molecule to form hydronium, H3O+.
</span>
I believe the correct answer from the choices listed above is the third option. The ion would be Al+3. It is obvious because among the options, this is the only substance that has a charge. <span>An </span>ion<span> is an atom or a molecule in which the total number of electrons is not equal to the total number of protons, giving the atom or molecule a net positive or negative electrical charge. </span>
Because it is balanced with protons and electrons
Answer:
% sodium= 13.6 % sodium
% carbon= 35.5 % carbon
% hydrogen= 4.7% hydrogen
% nitrogen = 8.3% nitrogen
% oxygen = 37.8 % oxygen
Explanation:
To find its percent composition means that we are to find to find the percentage of each of the constituents of the compound present.
The molar mass of monosodium glutamate is 169.11 gmol-1
Hence;
Percent of sodium= 23 gmol-1/169.11 gmol-1 × 100 = 13.6 % sodium
Percent of Carbon= 60 gmol-1/169.11 gmol-1 ×100 = 35.5 % carbon
Percent of hydrogen= 8/169.11 gmol-1 ×100 = 4.7% hydrogen
Percent nitrogen = 14/169.11 gmol-1 × 100 = 8.3% nitrogen
Percent oxygen = 64/169.11 gmol-1 ×100 = 37.8 % oxygen
