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zheka24 [161]
3 years ago
7

Slope -2 passes through (-7,2) Find the equation of the line.

Mathematics
1 answer:
maw [93]3 years ago
3 0

Answer: sorry

Step-by-step explanation:

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Step-by-step explanation:

First, the problem is g(f(x)). You would plug in f(x) wherever you see an x in g(x). To find the domain, you take the bottom function, and set it equal to 0.

\sqrt{x-2} =0

When you solve that, you get x=2. You know your domain is x≥2, but there is as asymptote at x=11. That means the graph never reaches x=11, but gets very close. You find that by setting the entire equation equal to 0 and solve from there.

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D i think

Step-by-step explanation:

7 0
3 years ago
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Hehas 337 dollrs because 220:65% is one so that is it
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3 years ago
If f(x)=4x^2+1 and g(x) =x^2-5 find (f-g)(x)
docker41 [41]

Answer:

\huge\boxed{(f-g)(x)=3x^2+6}

Step-by-step explanation:

(f-g)(x)=f(x)(x)\\\\\text{substitute}\ f(x)=4x^2+1\ \text{and}\ g(x)=x^2-5\\\\(f-g)(x)=(4x^2+1)-(x^2-5)=4x^2+1-x^2-(-5)=4x^2+1-x^2+5\\\\\text{combine like terms}\\\\(f-g)(x)=(4x^2-x^2)+(1+5)=3x^2+6

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Step-by-step explanation:

6x>3

x>1/2

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