Answer: D. They are made up of hard spheres that are in random motion.
Explanation:
A gas is a <u>state of aggregation of matter</u> in which, under certain conditions of temperature and pressure, <u>its molecules interact weakly with each other, without forming molecular bonds</u>, adopting the shape and volume of the container that contains them and tending to separate everything possible because of its <u>high concentration of kinetic energy</u>.
The molecules of a gas are practically <u>free</u> and have the ability to be distributed throughout the space in which they are contained because <u>the gravitational forces and attraction between them are practically negligible</u> compared to the speed at which they move. .
Therefore, gas molecules do not travel specific trajectories or vibrate in a stationary position, instead <u>they move quickly and randomly through the entire space of the container that contains them.</u>
Answer:
volume is the amount of space something occupies
Explanation:
When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.
<h3>What is Limiting reagent ?</h3>
Limiting reagents are the substances that are completely consumed first in a chemical reaction.
Given ;
- Amopunt of Zn : 1 mole
- Amount of O₂ : 2 mole
Given equation ;
2Zn + O₂ --> 2ZnO
As according to given chemical equation,
2 moles Zn of reacts with 1 mole of O₂ to produce 2 moles of ZnO.
Therefore,
1 mole of Zn will require 0.5 mole of O₂.
But,
the given amount of O₂ is 2 mole which is excess
Hence,
Zn here will act as the Limiting reagent, According to which the amount of product formed will be decided.
Therefore,
If 2 mole Zn produces : 2 moles of ZnO (According to given balanced equation)
Thus,
1 mole of Zn will produce = 2/2 x 1
= 1 mole of ZnO
Hence, When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.
Learn more about Limiting reagent here ;
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Answer:
1.55 mol
Step-by-step explanation:
We can use the <em>Ideal Gas Law</em> to solve this problem.
pV = nRT Divide both sides by RT
n = (pV)/(RT)
Data:
p = 1.40 atm
V = 27.5 L
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = 302 K
Calculations:
n = (1.40 × 27.5)/(0.082 06 × 302)
= 1.55 mol
<span>Here's your balanced chemical equation:
Pb(NO3)2</span><span> (aq) + K2SO4 (aq) </span>⇒<span> PbSO4 (s) + 2KNO3 (aq)
Therefore the precipitate formed is </span>lead(II) <span>sulfate.</span>
