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3 years ago

Can someone help me!

Mathematics

1 answer:

givi [52]3 years ago

5 0

I think it might be 1/5 cup maybe

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What are the correct answers and why? Simple and concise explanation please!!!

dezoksy [38]

Answer:

$\large\boxed{-\bigg[(x-3)^2+2x\bigg]+1}\\\\\boxed{-x^2+4x-8}$

Step-by-step explanation:

$(g\ \circ\ f)(x)=g\bigg(f(x)\bigg)$

$f(x)=(x-3)^2+2x\\\\g(x)=-x+1\\\\g\ \circ\ f\to\text{put f(x) instead of x in the function g(x)}:\\\\(g\ \circ\ f)(x)=-\bigg[\underbrace{(x-3)^2+2x}_{x}\bigg]+1$

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$-\bigg[(x-3)^2+2x\bigg]+1=-(x-3)^2-2x+1\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=-(x^2-(2)(x)(3)+3^2)-2x+1=-(x^2-6x+9)-2x+1\\\\=-x^2-(-6x)-9-2x+1=-x^2+6x-9-2x+1\\\\\text{combine like terms}\\\\=-x^2+(6x-2x)+(-9+1)=-x^2+4x-8$

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$-x^2+4x-8=-x^2+4x-2^2+2^2-8=-(x^2-4x+2^2)+4-8\\\\=-(\underbrace{x^2-(2)(x)(2)+2^2}_{(a-b)^2=a^2-2ab+b^2})-4=-(x-2)^2-4=-(x+1-3)^2-4$

$In\ (-x+1-3)^2+2x,\ x^2\ will\ be\ positive.\\In\ (-x+1-3)^2+2(-x+1),\ x^2\ will\ be\ positive.$

6 0

3 years ago

Read 2 more answers

HELP PLEASE<3 Find the missing angle Btw its trigonometry

ira [324]

Answer:

x = 16.6

Step-by-step explanation:

Since we know the measure of an acute angle (31 degrees) of a right angle triangle, and of the side opposite to the angle (10), and we need to find the measure of the adjacent side "x", we use the tangent function:

$tan(\theta) = \frac{opposite}{adjacent} \\tan(31^o)=\frac{10}{x}\\x=\frac{10}{tan(31^o)} \\x \approx 16.64279$

which rounded to one decimal is

x = 16.6

6 0

3 years ago

Need the work for this. 192 is the answer

Art [367]

Replace x with 3:

y = -3 *4^3

y = -3 * 64

y = -192

6 0

4 years ago

7(2x-5)-11=3(5x-2)-2x

ICE Princess25 [194]

Answer:

x=40

Step-by-step explanation:

7(2x-5)-11=3(5x-2)-2x Distribute

14x-35-11=15x-6-2x Simplify

14x-46=13x-6 subtract 13x and add 46

x=40

5 0

3 years ago

Charlie used these steps to solve the equation 6x+5=1+2(3x+2)6x+5=1+23x+2. Which choice describes the meaning of his result, 5

zaharov [31]

We have that
[6x+5]=1+2*(3x+2)
[6x+5]=1+2*3x+2 --------> is not correct ------->1+ 2*(3x+2)=1+2*3x+2*2

then
[6x+5]=1+6x+4---------------> [6x+5]=[6x+5]

this equation is an identity, all real numbers are solutions.

5 0

3 years ago

Read 2 more answers