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UkoKoshka [18]
3 years ago
12

There are four cards numbered 1 through 4. The number 2 card is chosen randomly and not replaced. Find the probability of choosi

ng a second card that is the number 3.
Mathematics
1 answer:
malfutka [58]3 years ago
3 0

Answer:

1/3

Step-by-step explanation:

since number 2 card was not replaced, we have;

probability of picking a second card, 3;

let S be number of sample space

n(S)= 4

n(3)= 1

Pr(3/2)= 1/3

(because since one was already chosen and n, the sample space would reduce)

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Answer:

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3 years ago
I need help with my homework please answer this correctly
Bogdan [553]

2 numbers can be represented by the variables x and y.

Set up a system of equations:

x + y = 33

x - y = 1

The two numbers added together will result in a sum of 33. However, one number subtracted from another will result in a difference of 1.

In both systems of equations, there are inverses of variable y. Therefore, we can combine the systems of equations by adding them together:

(x + x) + (y - y) = (33 + 1)

2x = 34

Divide both sides by 2 to get x by itself:

x = 17

One of the numbers will be 17.

Plug the value into one of the equations:

17 - y = 1

Add y to both sides:

17 = y + 1

Subtract both sides by 1 to get y by itself:

y = 16

The two numbers that sum up to 33, with a difference of 1 between them, will be 16 and 17.

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3 years ago
Tom has r quarters. Express the value of the quarters in cents.
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C = 0.25r

this is becasue quarters have a value of 0.25 and c is the total cents

hope this helps and have a great day! :)
3 0
3 years ago
Solve the equation -3 = 8x - 4yfor y
Anestetic [448]

You would add 4y to both sides of the equation which would leave you with

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then you would divide the entire equation by 4 leaving you with

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then you would add 3/4 to both sides of the equation leaving you with

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Answer:

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Step-by-step explanation:

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