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Rudiy27
3 years ago
5

Question 2

Mathematics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

No

Step-by-step explanation:

1. Plug the values into the equation: 6 \geq  -2(5)-4

2. Expand the inequality: 6 \geq -14

3. Determine if true/false.

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The ratio of the <em>lateral surface</em> area of cone A to the <em>lateral surface</em> area of cylinder B is equal to r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}. (Correct choice: False)

<h3>What is the ratio of lateral area of cone to the lateral area of the cylinder?</h3>

In accordance with <em>space</em> geometry, the <em>lateral</em> areas of the cone and cylinder are described by the following equations:

Cone

A_{l} = \pi \cdot r \cdot \sqrt{r^{2}+h^{2}}     (1)

Cylinder

A_{l} = 2\pi\cdot r\cdot h     (2)

If we divide (2) by (1), then we have the following ratio:

r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}

The ratio of the <em>lateral surface</em> area of cone A to the <em>lateral surface</em> area of cylinder B is equal to r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}. (Correct choice: False)

To learn more on surface areas: brainly.com/question/2835293

#SPJ1

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2 years ago
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Step-by-step explanation:

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Answer:

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