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DiKsa [7]
3 years ago
7

C2H5OH(g) + 302(g) → 2CO2(g) + 3H2O(g) + heat reaction type

Chemistry
1 answer:
Tcecarenko [31]3 years ago
5 0

Answer:

Combustion

Explanation:

The reaction type is a combustion reaction;

        Ethanol + oxygen gas  →  carbon dioxide + water

Now;

  Ethanol is the fuel and oxygen gas rapidly combines with it to form carbon dioxide and water.

  • This process releases heat energy from chemical bonds.
  • Most hydrocarbons burn in excess air or oxygen to give carbon dioxide and water.  
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What is the mass of an object if its height is 10 meters above ground and its gravitational potential energy (GPE) is 3920 Joule
Serjik [45]

Answer:

40

Explanation:

Your trying to find out the meters so your going to divide 3920J by 10 and 9.8

3920/10/9.8

8 0
3 years ago
The specific heat capacity of graphite is 0.71 J/°C g.
Tom [10]

Answer:

,,mknlmn

Explanation:

'.'.'.

8 0
3 years ago
A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil
Vaselesa [24]

Answer: 1.6L

Explanation:

V1 = 1.50 L,

V2 =?

n1 = 3mol

n2 = 3 + 0.2 = 3.2mol

From PV = nRT

V1 /n1 = V2/n2

1.5/3 = V2 /3.2

V2 = (1.5/3/) x 3.2 = 1.6L

5 0
3 years ago
Read 2 more answers
The mass percent of solute in a solution containing 3.73 g KBr dissolved in 131 g of H2O is:
Elina [12.6K]

\huge \underbrace \mathfrak \red{Answer}

28%

Explanation:

mass of solute(KBr) = 3.73g

mass of solvent(H2O) = 131g

mass of solution = mass of solute + mass of solvent

= 3.73 + 131

= 134.73g

\sf \large {mass \: percentage =  \frac{mass \: of \: solute}{mass \: of \: solvent}  \times 100} \\  \\  \sf  mass \: percentage =  \frac{3.73}{134.73}  \times 100 \\  \\  \sf mass \: percentage =  0.028 \times 100 \\  \\  \sf mass \: percentage = 28\%

7 0
2 years ago
134 grams of nitric acid is added to 512 grams of water. Calculate the molality of nitric acid.
Nana76 [90]

Answer:   4.15234 m

512 g H2O * \frac{1 kg}{1000 g} = 0.512 kg H2O

Nitric Acid:  HNO3 = 1.008 + 14.007 + 3(15.999) = 63.012 g/mol

H = 1.008 g/mol

N = 14.007 g/mol

O3 = 3*15.999

134 g HNO₃ * \frac{mol}{63.012 g} = 2.126 mol

m = \frac{2.126  mol}{0.512  kg} = 4.15234 m

6 0
3 years ago
Read 2 more answers
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