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melamori03 [73]
3 years ago
8

What is the energy that occurs in teh conversion of an ion ic solid to a widely spread gas?

Chemistry
1 answer:
lutik1710 [3]3 years ago
6 0

Answer:

The sublimation energy

Explanation:

When an ionic solid turns into a gas it is changing from solid state to gas state without going throught liquid state. This process is called sublimation and the energy will be equal to \Delta H_{sublimation}

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4 0
3 years ago
A solution is created by dissolving 11.0 grams of ammonium chloride in enough water to make 235 mL of solution. How many moles o
Amanda [17]

Answer:

The correct answer is 0.206 moles

Explanation:

According to the given scenario, the calculation of the number of moles of ammonium chloride is available in the resulting solution is given below:

Given that

Amount of NH_4Cl is 11.0 grams

And, the volume is 235 mL

Now the molar mass of NH_4Cl is 53.49g/mol

So, the number of moles presented is

= 11.0 ÷ 53.49

= 0.206 moles

hence, the number of moles of ammonium chloride are available in the resulting solution is 0.206 moles

7 0
3 years ago
What types of organisms are most likely to become extinct (characteristics)?
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Many rare and/or endemic species exhibit one or more of the following attributes which make them especially prone to extinction: (1) narrow (and single) geographical range, (2) only one or a few populations, (3) small population size and little genetic variability, (4) over-exploitation by people
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3 years ago
What type of fault usually occurs because of compression?
lianna [129]

Answer:c

Explanation:

4 0
3 years ago
Read 2 more answers
The half-life of tritium (H-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a
Rudiy27

Answer:

The amount left after 49.2 years is 3mg.

Explanation:

Given data:

Half life of tritium = 12.3 years

Total mass pf tritium = 48.0 mg

Mass remain after 49.2 years = ?

Solution:

First of all we will calculate the number of half lives.

Number of half lives = T elapsed/ half life

Number of half lives =  49.2 years /12.3 years

Number of half lives =  4

Now we will calculate the amount left after 49.2 years.

At time zero 48.0 mg

At first half life = 48.0mg/2 = 24 mg

At second half life = 24mg/2 = 12 mg

At 3rd half life = 12 mg/2 = 6 mg

At 4th half life =  6mg/2 = 3mg

The amount left after 49.2 years is 3mg.

6 0
4 years ago
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