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3 years ago

What are the biotic and abiotic factors of a desert?

2 answers:

7 0

Biotic factors are the living components or parts of an ecosystem. So the biotic factors would be cacti, salamanders, lizards, and other animals living in a desert. Abiotic factors are the nonliving components in an ecosystem. Some abiotic factors are sand, soil, rocks, and minerals. Hope this helps.

FrozenT [24]3 years ago

6 0

Biotic factors: a cactus, animals. They are living things. Abiotic factors: sand, rocks. They are non living things.

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Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr

VikaD [51]

Answer : The value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

Explanation :

The balanced cell reaction will be,

$Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)$

The half-cell reactions are:

Oxidation reaction (anode) : $Pb(s)\rightarrow Pb^{2+}(aq)+2e^-$

Reduction reaction (cathode) : $2Ag^+(aq)+2e^-\rightarrow 2Ag(g)$

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

$\Delta G^o$ = standard Gibbs free energy

F = Faraday constant = 96500 C

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = 0.93 V

Now put all the given values in the above formula, we get:

$\Delta G^o=-2\times 96500\times 0.93$

$\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol$

Now we have to calculate the value of 'K'.

$\Delta G^o=-RT\ln K$

where,

$\Delta G_^o$ = standard Gibbs free energy = -180 kJ/mol

R = gas constant = $8.314\times 10^{-3}kJ/mole.K$

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

$-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K$

$K=3.6\times 10^{31}$

Therefore, the value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

5 0

3 years ago

When 5ml of HCl was added

777dan777 [17]

Answer:

A. There was still 140 ml of volume available for the reaction

Explanation:

According to Avogadro's law, we have that equal volumes of all gases contains equal number of molecules

According to the ideal gas law, we have;

The pressure exerted by a gas, P = n·R·T/V

Where;

n = The number of moles

T = The temperature of the gas

R = The universal gas constant

V = The volume of the gas

Therefore, given that the volumes and number of moles of the removed air and added HCl are the same, the pressure and therefore, the volume available for the reaction will remain the same

There will still be the same volume available for the reaction.

5 0

3 years ago

When a rock falls from outer space all the way to the groung, its called a?

goblinko [34]

It's called a meteorite.

6 0

3 years ago

Given bh3, o3, co2, and nh3, which of these compound is an exception to the octet rules?.

Ghella [55]

Answer:

a. BH₃

Explanation:

According to the octet rules, atoms reach stability when are surrounded by eight electrons in their valence shell when they combine to form a chemical compound.

From the options, the only compound in which the central atom does not meet the octet rules is BH₃. The central atom is boron (B), which has 3 electrons in its valence shell. When B is combined with hydrogen (H), 3 electrons from the 3 atoms of H are added. The total amount of electrons is 6, fewer than 8 electrons needed to meet the rule.

hope this helps

5 0

2 years ago

In the chemical reaction: NaOH (s) + H2O Na+ (aq) + OH- (aq), which substance (or substances) is in solution? A. Na+ (aq) only B

bonufazy [111]

Answer:

in a chemical reaction of NaOH with H2O, after NaOH is completely disassociated, we will find Na+ and OH- ions in the solution. (option C).

Explanation:

In a reaction where NaOH is added to H2O.

NaOH is considered a strong base, this means that in an aqueous solution ( in water) it's able to completely disassociate in ions.

There will not remain any NaOH in the solution. This means option D is not correct.

The ions in which NaOH will disassociate are : NaOH → Na+ + OH-

These ions we will find in the solution.

Not only Na+ because NaOH is a strong base, so there will be a lot of OH- ions as well in solution.

This means in a chemical reaction of NaOH with H2O, after NaOH is completely disassociated, we will find Na+ and OH- ions in the solution.

3 0

3 years ago