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aleksklad [387]
3 years ago
9

he lifespan of the Ebola virus on flat dry surfaces has a normal distribution with μ = 643.6 minutes and σ = 77.7 minutes. You m

onitor a random sample of size n = 61 . What is the mean of the distribution of sample means?
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

By the Central Limit theorem, the mean of the distribution of sample means is 643.6 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem

The mean of the population is 643.6 minutes.

By the Central Limit theorem, the mean of the distribution of sample means is 643.6 minutes.

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I'm pretty sure you would need to multiply 2/5 by 40.

So, if you multiply 2/5 by 40, you need to turn 40 into a fraction with 1 being the denominator.

2/5 x 40/1 = 80/5

Since the product is an improper fraction, you would simplify it to a whole number.

80/5 = 16. 

He can expect to hit it 16 times to get a hole in one.

I hope I am right and have a great day.

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Answer:

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3 years ago
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If you dont understand just coment.

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