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aleksklad [387]
3 years ago
9

he lifespan of the Ebola virus on flat dry surfaces has a normal distribution with μ = 643.6 minutes and σ = 77.7 minutes. You m

onitor a random sample of size n = 61 . What is the mean of the distribution of sample means?
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

By the Central Limit theorem, the mean of the distribution of sample means is 643.6 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem

The mean of the population is 643.6 minutes.

By the Central Limit theorem, the mean of the distribution of sample means is 643.6 minutes.

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g The tensile 0.2 percent offset yield strength of AISI 1137 cold-drawn steel bars up to 1 inch in diameter from 2 mills and 25
Vitek1552 [10]

Answer:

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Step-by-step explanation:

Given the following :

Midpoint (S)____F

S y 93 95 97 99 101 103 105 107 109 111 f 19 25 38 17 12 10 5 4 4 2

Calculating the mean and standard deviation using a calculator :

The mean(m) of the data above = 98.12

Standard deviation (sd) = 4.02

Proportion = 99% of population

From z table = 2.33

Using :

Zscore =(x - m) / sd

2.33 = (x - 98.12) / 4.02

2.33 * 4.02 = x - 98.12

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x = 107.4866

X = 107.50

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3 years ago
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You answer is 3 and here's why...

7x + 5 - 3x - 7 = 10

First you must collect like terms

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