Answer:
I don’t understand Espanol
Explanation:
sorry
Temperature that will be my answer number 1
Infrared is created by detecting the produced radiation coming off of clouds. The temperature of the cloud will define the wavelength of radiation produced from the cloud. The benefit of the infrared imagery is that can be used day and night to conclude the temperature of the cloud tops and earth surface structures and to get the general idea of how clouds are. Based on the general guidelines to define cloud features, if the cloud is bright white on infrared then it is a high cloud or has a cloud top that is developed high into the troposphere. In this way infrared images actually display patterns of temperature on a gray scale such that at one extreme dark gray is warm and at the other extreme bright white is cold. A color scale is used to portray temperature and some improved infrared images show two or more gray scale sequences. High cold clouds are brighter white than low warm clouds.
Answer:
35 N to the right.
Explanation:
450 is going to the right so you subtract what is going against it. Which gives you 35. And because 450 is bigger than 415, it'll be going to the right.
Given:
Area of pool = 3m×4m
Diameter of orifice = 0.076m
Outlet Velocity = 6.3m/s
Accumulation velocity = 1.5cm/min
Required:
Inlet flowrate
Solution:
The problem can be solved by this general formula.
Accumulation = Inlet flowrate - Outlet flowrate
Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice
First, we need to convert the units of the accumulation velocity into m/s to be consistent.
Accumulation velocity = 1.5cm/min × (1min/60s)×(1m/100cm)
Accumulation velocity = 0.00025 m/s
We then calculate the area of the pool and the area of the orifice by:
Area of pool = 3 × 4 m²
Area of pool = 12m²
Area of orifice = πd²/4 = π(0.076m)²/4
Area of orifice = 0.00454m²
Since we have all we need, we plug in the values to the general equation earlier
Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice
0.00025 m/s × 12m² = Inlet flowrate - 6.3m/s × 0.00454m²
Transposing terms,
Inlet flowrate = 0.316 m³/s
