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Aloiza [94]
2 years ago
9

. A telescope is constructed with two lenses separated by a distance of 25 cm. The focal length of the objective is 20 cm. The f

ocal length of the eyepiece is 5 cm. Calculate the magnitude of the angular magnification of the telescope.
Physics
1 answer:
beks73 [17]2 years ago
5 0

Answer:

the magnitude of the angular magnification of the telescope. is 4

Explanation:

Calculate the magnitude of the angular magnification of the telescope.

Given that,

distance = 25cm

focal length from the objective f₀ = 20cm

focal length from eye piece f₁ = 5cm

The angular magnification of the telescope is

M = \frac{f_0}{f_1}

Magnification = 20 / 5

magnification = 4

Hence, the magnitude of the angular magnification of the telescope. is 4

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the frequency of a beam of uv light is 1.0 ×10 ^15hz what is the energy in one quantum of this light express it in ev? ​
kap26 [50]

Answer:

4.14 eV

Explanation:

f = 1.0 ×10^15 Hz

h= 6.63×10^-34 J s (  this is called PLANCK 'S CONSTANT)

ENEGY = E = ?

E = hf  ( THIS IS FORMULA FOR ENERGY OF ONE QUANTA OR ONE PHOTON )

E= 6.63×10^-34×1.0 ×10^15

E = 6.63×10^-19 J

As 1eV = 1.6×10^-19 J so changing energy in eV from joules we will divide energy by 1.6×10^-19

hence E in eV = 6.63×10^-19/(1.6×10^-19)

          E = 4.14 eV

7 0
3 years ago
An object is floating in equilibrium on the surface of a liquid. The object is then removed and placed in another container, fil
Anestetic [448]

Answer:

The fraction of its volume inside liquid  is increased .

Explanation:

According to principle pf floatation , an object floats on the surface of water

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In the second case , when the body is dipped into liquid of lesser density , in order to balance the weight of body , more volume of liquid will be displaced so that weight of displaced liquid becomes equal to object's weight . So the body floats with greater depth inside liquid . The fraction of its volume inside liquid  is increased .

4 0
2 years ago
{WILL GIVE (Brain lies t) TO FULL ANSWERS}
kap26 [50]

Answer:

1: surface temperature

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4 0
2 years ago
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A rural mail carrier logged the mileage on the odometer at the start of the mail route as 31,500 miles. After 6.5 hours, the car
dusya [7]

Answer:32.77\ mi/hr

Explanation:

Given

Initially Reading on the odometer is 31,500\ miles

Final reading on the odometer is 31,713\ miles

Time taken is t=6.5\ hr

average velocity =\dfrac{\text{Displacement}}{\text{time}}

v_{avg}=\dfrac{31713-31500}{6.5}

v_{avg}=\dfrac{213}{6.5}

v_{avg}=32.77\ mi/hr

Thus the average velocity of mail truck is 32.77\ mi/hr

8 0
3 years ago
There is a 50 g sample of Ra-229. It has a half-life of 4 minutes.
Sloan [31]

Via half-life equation we have:


A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h} }


Where the initial amount is 50 grams, half-life is 4 minutes, and time elapsed is 12 minutes.  By plugging those values in we get:

A_{final}=50(\frac{1}{2})^\frac{12}{4}=50(\frac{1}{2})^{3}=50(\frac{1}{8})=6.25g


There is 6.25 grams left of Ra-229 after 12 minutes.

4 0
3 years ago
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