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Aloiza [94]
2 years ago
9

. A telescope is constructed with two lenses separated by a distance of 25 cm. The focal length of the objective is 20 cm. The f

ocal length of the eyepiece is 5 cm. Calculate the magnitude of the angular magnification of the telescope.
Physics
1 answer:
beks73 [17]2 years ago
5 0

Answer:

the magnitude of the angular magnification of the telescope. is 4

Explanation:

Calculate the magnitude of the angular magnification of the telescope.

Given that,

distance = 25cm

focal length from the objective f₀ = 20cm

focal length from eye piece f₁ = 5cm

The angular magnification of the telescope is

M = \frac{f_0}{f_1}

Magnification = 20 / 5

magnification = 4

Hence, the magnitude of the angular magnification of the telescope. is 4

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Spring #1 has a force constant of k, and spring #2 has a force constant of 2k. Both springs are attached to the ceiling. Identic
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Therefore by balancing the forces, we get

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⇒x1=w/k

Energy stored in a spring is given by \frac{1}{2}kx^{2} where k is the force constant and x is the extension in spring.

Therefore Energy stored in spring#1 is, \frac{1}{2}k(x1)^{2}

                                                              ⇒\frac{1}{2}k(\frac{w}{k})^{2}

                                                              ⇒\frac{w^{2}}{2k}

Spring #2:

Force constant= 2k

let x2 be the extension in spring#2

Therefore by balancing the forces, we get

Spring force= weight

⇒2k·x2=w

⇒x2=w/2k

Therefore Energy stored in spring#2 is, \frac{1}{2}2k(x2)^{2}

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                                                              ⇒\frac{w^{2}}{4k}

∴The ratio of the energy stored by spring #1 to that stored by spring #2 is \frac{\frac{w^{2}}{2k}}{\frac{w^{2}}{4k}}=2:1

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