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Gemiola [76]
4 years ago
6

The ________ is the difference between the volume in the combustion chamber above the piston when the piston is at bottom dead c

enter (BDC) and the volume of the combustion chamber above the piston when the piston is at top dead center (TDC).
Physics
1 answer:
Vitek1552 [10]4 years ago
3 0

Answer: Compression ratio

Explanation:

Let's begin by explaining that in a combustion chamber there are pistons that move up and down within cylinders. If we take as an example one cylinder, we will have the following:

-The bottom dead center (BDC) is when the volume in the combustion chamber is the greatest, because the piston is exactly at the bottom of the cylinder.

- The top dead center (TDC) is  when the volume in the combustion chamber is the lowest, because the piston is at the top (the highest point) inside the cylinder.

Now, the ratio between these two volumes is the Compression ratio.

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A 48.0-kg astronaut is in space, far from any objects that would exert a significant gravitational force on him. He would like t
marusya05 [52]

Answer:

The astronaut is moving at a speed of 0.36m/s

Explanation:

Speed here corresponds to velocity

The astronaut's mass = 48kg

velocity of astronaut = ?

mass of socket = 0.72kg

velocity of socket = 5m/s

mass of the spanner = 0.8kg

velocity of spanner = 8m/s

change in time = 0.05 -0 = 0.05sec

mass of the mallet = 1.2kg

velocity of mallet = 6m/s

change in time = 9.9 -0 = 9.9sec

To find the astronaut velocity, we would calculate the total momentum which is the astronaut.

∑momentum (M) = ∑astronaut momentum

∑M = ∑astronaut M

∑astronaut M = M of socket + M of spanner + M of mallet

momentum = mass × velocity

(mass × velocity)of astronaut = (0.72×5) + (0.8×8) + (1.2×6)

48 × velocity of astronaut= 3.6 + 6.4 + 7.2

48 × velocity of astronaut= 17.2

velocity of astronaut = 17.2/48

velocity of astronaut = 0.36m/s

The astronaut is moving at a speed of 0.36m/s

5 0
3 years ago
Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile? Answ
Vinil7 [7]

Answer: 272.82 drop/tile

Explanation:

Given that the Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile?

Tiles/ft^2 × drop/tiles = drop/ft^2

Tiles will cancel out. Leaving the answer to be drop/ ft^2

Substitutes all the magnitude of the above units.

17 × drop/tiles = 4638

Make drop/tiles the subject of formula

Drop/tiles = 4638/17

Drop/tiles = 272.82

Therefore, 272.82 drop/tile drops fall on each tile? 

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3 years ago
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Rain is considered a precipitate. Along with: drizzle, sleet, snow and hail.

hope this helps :)

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4 years ago
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There are an estimated 100 billion, so the answer would be D.) Billions
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I think it’s kinetic energy
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