3 years ago

What is the equation of a parabola with its vertex at the origin and its focus at (–2, 0)?

Mathematics

1 answer:

user100 [1]3 years ago

7 0

Step-by-step explanation:

this is the answerI hope it helps

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In the recursive formula an = an−1 + 5, the value of the previous term is represented by

den301095 [7]

Step-by-step explanation:

In the recursive formula an = an−1 + 5

$a_n = a_{n-1}+5$

Suppose if a_5 is the nth term then previous term is a_4

To get the previous term we need to subtract 1 from the n

So a_n is the nth term

$a_{n-1}$ is the previous term

Here 5 represents the common difference between two terms

So value of previous term is represented by

$a_{n-1}$

Answer : $a_{n-1}$

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3 years ago

Hint( not 8,even tho no one is gonna guess it anyways lol)<br> 4² - 6 ÷ 2 + 3

Kitty [74]

The answer is 2 cause you have to do the asides individually

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Solve the proportion for n. 36/8 = n/4

fomenos

Answer:

N = 18

Step-by-step explanation:

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HELP ASAP!! (picture above)

lilavasa [31]

To calculate minimum value, do -b/2a to get the x-value, and plug it in to get the y-value:

-6/8 = -3/4

$4 * (-\frac{3}{4} )^{2} + 6 (-\frac{3}{4} ) - 18 = \frac{9}{4} - \frac{9}{2} - 18 = - \frac{81}{4}$

So the minimum value of g(x) is -81/4

This shows that g(x) has a lesser minimum value than f(x)

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