Answer:
c. 0.810
Step-by-step explanation:
Given, total % of satisfactory packages = 90% = 0.90
Now, since selecting a satisfactory package is independent of any other trials (i.e. all the selection trials are independent to each other)
Hence, Probability of selecting two packages that re satisfactory
P(Selecting 2 satisfactory packages) = (0.90)^2
P(Selecting 2 satisfactory packages) = 0.90*0.90
P(Selecting 2 satisfactory packages) = 0.810
Note: We are selecting product since the chance of selecting in each trials are independent.
4: linear
5: quadratic
6: exponential
7: inverse variation
Answer:
(A) 0.297
(B) 0.595
Step-by-step explanation:
Let,
H = a person who suffered from a heart attack
G = a person has the periodontal disease.
Given:
P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15
Compute the probability that a person has the periodontal disease as follows:

(A)
The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.
(B)
Now if the probability of a person having a heart attack is, P (H) = 0.38.
Compute the probability that a person has the periodontal disease as follows:

Compute the probability of a person having a heart attack given that he or she has the disease:

The probability of a person having a heart attack given that he or she has the disease is 0.595.
What is the problem I can help but there is none.
LN=8 because every time there is a midpoint you have to divide it in half. So 64,32,16,8