Answer:
2.5e-0.04x = 1.2 + 0.2x
Step-by-step explanation:
Given that:
Insect A:
Initial population, Po = 2.5 million
Rate of decline = 4%
Insect B:
Initial Population (Po) = 1.2 million
Yearly increase = 200,000 = (200,000/1,000,000) = 0.2
For insect A:
P(t) = Po(1 - r)^t = Po*e^-rt
Po*e^-rt = 2.5e^-0.04t ----(1)
For Insect B:
P(t) = Po + (yearly increase) * t
P(t) = 1.2 + 0.2t - - - - - (2)
Equating (1) and (2)
2.5e^-0.04t = 1.2 + 0.2t
I got 1.4 for this one..............
At this point in time, you can use a technique called cross-mutiplication, where you say that
, and
at this point in time, you can devide each side by 8 and solve
I hope this helps you
4,8 (x+4)=2,16
48 (x+4)=21,6
x+4=21,6/48
x+4= 0,45
x=0,45-4
x= -3,55
