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3 years ago

5 miles= km. how many km in 250 miles

Mathematics

1 answer:

horsena [70]3 years ago

5 0

Using that 1 mile = 1,6 km so 5 miles = 5*1,6 = 8 km

and 250 miles = 250*1,6 = 400 km

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A spherical balloon has a circumference of 25 cm.

worty [1.4K]

The approximate surface area of the balloon is 199 cm².

The approximate volume of the balloon is 262 cm³

<h3>What is the surface area and the volume of the balloon? </h3>

Radius of the balloon = circumference / 6.2832

25 / 6.2832 = 3.98cm

Surface area = 4πr²

4 x 22/7 x 3.97² = 199 cm²

Volume = 4/3πr³

4/3 x 22/7 x 3.97³ = 262.20 cm³

To learn more about the volume of a sphere, please check: brainly.com/question/13705125

5 0

3 years ago

Apply the appropriate mathematical operation to solve this fulcrum problem.

ale4655 [162]

<h2>Hello!</h2>

The answer is:

The second distance ( $distance_{2}$ ) is equal to 7.5 feet.

Since we are given two forces acting at distance, torque will be created. We are given two forces and one distance, so, to calculate the other distance required to balance the system (solve this fulcrum problem), we need to write the following equation:

$Torque_{1}=Torque_{2}$

Where,

$Torque=F*Distance$

We are given,

$Force_{1}=Weight_{1}=150lb\\Force_{2}=Weight_{2}=30lb\\distance_{1}=15ft\\$

So, substituting and calculating, we have:

$Torque_{1}=Torque_{2}$

$Weight_{1}*distance_{1}=Weight_{2}*distance_{2}$

$150lb*15ft=300lb*distance_{2}$

$distance_{2}=\frac{150lb*15ft}{300lb}=7.5ft$

Hence, the second distance ( $distance_{2}$ ) is equal to 7.5 feet.

It's a logical solution since the second force is twice the first force and it means that the second distance must be equal to half the first distance in order to maintain the equilibrium condition.

Have a nice day!

8 0

3 years ago

A business knew that 30%, percent of its customers were less than 25 years old. The business wanted to increase this percentage,

jeyben [28]

Answer:

The answer is "0.9258201 or $\bold{ \frac{0.36 -0.3}{\sqrt{\frac{0.3 \times 0.7 }{50}}}}$ ".

Step-by-step explanation:

$\to P= 30 \ \%\\\\ \to x= 18 \\\\ \to n=50\\\\\\\hat p= \frac{x}{n} = \frac{18}{50} = 0.36 \\\\\bold{Formula:}\\\\X= \frac{\hat p -p}{\sqrt{\frac{p \times (1-p)}{n}}}\\\\$

$= \frac{0.36 -0.3}{\sqrt{\frac{0.3 \times (1-0.3)}{50}}}\\\\= \frac{0.36 -0.3}{\sqrt{\frac{0.3 \times 0.7 }{50}}}\\\\= \frac{0.36 -0.3}{\sqrt{\frac{0.21}{50}}}\\\\= \frac{0.06}{\sqrt{0.0042}}\\\\= \frac{0.06}{0.064807407}\\\\= 0.9258201$