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3 years ago

PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

xxMikexx [17]3 years ago

4 0

Answer:

the equation: 2x+3+2x+3+2x= 36

x=5

the length of the congruent sides

the length of the third side

Step-by-step explanation:

i'll add this later hold on

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Suiting at 6 a.m., cars, buses, and motorcycles arrive at a highway loll booth according to independent Poisson processes. Cars

dem82 [27]

Answer:

Step-by-step explanation:

From the information given:

the rate of the cars = $\dfrac{1}{5} \ car / min = 0.2 \ car /min$

the rate of the buses = $\dfrac{1}{10} \ bus / min = 0.1 \ bus /min$

the rate of motorcycle = $\dfrac{1}{30} \ motorcycle / min = 0.0333 \ motorcycle /min$

The probability of any event at a given time t can be expressed as:

$P(event \ (x) \ in \ time \ (t)\ min) = \dfrac{e^{-rate \times t}\times (rate \times t)^x}{x!}$

∴

(a)

$P(2 \ car \ in \ 20 \ min) = \dfrac{e^{-0.20\times 20}\times (0.2 \times 20)^2}{2!}$

$P(2 \ car \ in \ 20 \ min) =0.1465$

$P ( 1 \ motorcycle \ in \ 20 \ min) = \dfrac{e^{-0.0333\times 20}\times (0.0333 \times 20)^1}{1!}$

$P ( 1 \ motorcycle \ in \ 20 \ min) = 0.3422$

$P ( 0 \ buses \ in \ 20 \ min) = \dfrac{e^{-0.1\times 20}\times (0.1 \times 20)^0}{0!}$

$P ( 0 \ buses \ in \ 20 \ min) = 0.1353$

Thus;

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.1465 × 0.3422 × 0.1353

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.0068

(b)

the rate of the total vehicles = 0.2 + 0.1 + 0.0333 = 0.3333

the rate of vehicles with exact change = rate of total vehicles × P(exact change)

$= 0.3333 \times \dfrac{1}{4}$

= 0.0833

∴

$P(zero \ exact \ change \ in \ 10 minutes) = \dfrac{e^{-0.0833\times 10}\times (0.0833 \times 10)^0}{0!}$

P(zero exact change in 10 minutes) = 0.4347

The probability of the 7th motorcycle after the arrival of the third motorcycle is:

$P( 4 \ motorcyles \ in \ 45 \ minutes) =\dfrac{e^{-0.0333\times 45}\times (0.0333 \times 45)^4}{4!}$

$P( 4 \ motorcyles \ in \ 45 \ minutes) =0.0469$

Thus; the probability of the 7th motorcycle after the arrival of the third one is = 0.0469

P(at least one other vehicle arrives between 3rd and 4th car arrival)

= 1 - P(no other vehicle arrives between 3rd and 4th car arrival)

The 3rd car arrives at 15 minutes

The 4th car arrives at 20 minutes

The interval between the two = 5 minutes

<u>For Bus:</u>

P(no other vehicle other vehicle arrives within 5 minutes is)

= $\dfrac{6}{12} = 0.5$

<u>For motorcycle:</u>

$= \dfrac{2 }{12} = \dfrac{1 }{6}$

∴

The required probability = $1 - \Bigg ( \dfrac{e^{-0.5 \times 0.5^0}}{0!} \times \dfrac{e^{-1/6}\times (1/6)^0}{0!} \Bigg)$

= 1- 0.5134

= 0.4866

6 0

3 years ago

Michael wants to celebrate 4th July (US Independence Day) by putting together little gifts for his friends. He bought 176 red, 1

shepuryov [24]

Answer:

Step-by-step explanation:

2⊥ 96, 112, 176

2 48, 56, 88

2 24, 28, 44

2 12, 14, 22

2 6, 7, 11

Highest common factor= 2x2x2x2x2= 32

7 0

3 years ago

Sherman goes golfing every 6th day. and Brad goes golfing every 7th day.

mylen [45]

Find the least common multiple of each number:

6, 12, 18, 24, 30, 36, 42

7, 14, 21, 28, 35, 42

The least common multiple is 42, which means every 42 days they will golf on the same day.

3 0

3 years ago

Read 2 more answers

39 rounded to nearst 10

Vaselesa [24]

40 is the answer.........

7 0

3 years ago

What is the best approximation for the perimeter of a semicircle with a diameter of 12 cm?

Nesterboy [21]

First, we know that the equation for permeter of a circle is C=2*pi*4 or C=2*3.14*r if you are using 3.14 for pi. Since this is a semicircle, we simply divide this equation by 2 and plug in our radius (radius id 6 because 12/2 =6)

So we are using C=3.14*r
C=3.14*6
So the perimeter equals 18.84 so A

Hope this helps!

7 0

3 years ago

Read 2 more answers