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HACTEHA [7]
2 years ago
6

What is the area of a trapezoid that has bases measuring 19 centimeters and 23 centimeters, and a height of 14 centimeters? A =

h(b + b) ÷ 2 OR a = 1/2(h)(b+b)
Mathematics
1 answer:
Vsevolod [243]2 years ago
7 0

Answer:

A = h(b+b) /2

A = 14(23+19) /2

A = 588/2

A = 294cm^2

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1/2 - 3/11

Set both denominators (bottom numbers) to 22, so multiply the numerator of 1/2 by 11, and multiply the numerator of 3/11 by 2.

1/2 is now 11/22

3/11 is now 6/22

So, our new question is now : 11/22 - 6/22

Because the denominators are the same, all you have to do is simplify the top numbers.

So, 11-6 = 5

Therefore, your answer is 5/22

~Hope I helped!~
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Step-by-step explanation:

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