The numerator is 16 and the denominator is 3.
Answer:
$51.75
Step-by-step explanation:
Okay, so. They decreased there interest by .15. It is really nothing. So, we have no clue how many years. So, we will just use one year. We would start by multiplying 50 and 3.5% that will equal 1.75. Then we would add it up. 50 + 1.75, it will equal to 51.75.
Therefore your answer is $51.75
Hope this helps!
Answer:
X=-8
Step-by-step explanation:
A number x is multiplied by 4, added to 3, and then divided by x+2, leaving us with 7/2. Or, as an equation:
![\frac{4x + 3}{x + 2} = \frac{7}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4x%20%2B%203%7D%7Bx%20%2B%202%7D%20%20%3D%20%20%5Cfrac%7B7%7D%7B2%7D%20)
Now, let's cross multiply:
![2(4x + 3) = 7(x + 2)](https://tex.z-dn.net/?f=2%284x%20%2B%203%29%20%3D%207%28x%20%2B%202%29)
![8x + 6 = 7x + 14](https://tex.z-dn.net/?f=8x%20%2B%206%20%3D%207x%20%2B%2014)
And solve:
![x + 6 = 14](https://tex.z-dn.net/?f=x%20%2B%206%20%3D%2014)
![x = - 8](https://tex.z-dn.net/?f=x%20%3D%20%20-%208)
1/6* (15a+20b)
= 1/6* 15a + 1/6* 20b (Distributive property)
= 2.5a + 10/3*b
The final answer is 2.5a+ 10/3b
Hope this helps~
Answer:
The numbers of doors that will have no blemishes will be about 6065 doors
Step-by-step explanation:
Let the number of counts by the worker of each blemishes on the door be (X)
The distribution of blemishes followed the Poisson distribution with parameter
/ door
The probability mass function on of a poisson distribution Is:
![P(X=x) = \dfrac{e^{- \lambda } \lambda ^x}{x!}](https://tex.z-dn.net/?f=P%28X%3Dx%29%20%3D%20%5Cdfrac%7Be%5E%7B-%20%5Clambda%20%7D%20%5Clambda%20%5Ex%7D%7Bx%21%7D)
![P(X=x) = \dfrac{e^{- \ 0.5 }( 0.5)^ x}{x!}](https://tex.z-dn.net/?f=P%28X%3Dx%29%20%3D%20%5Cdfrac%7Be%5E%7B-%20%5C%200.5%20%7D%28%200.5%29%5E%20x%7D%7Bx%21%7D)
The probability that no blemishes occur is :
![P(X=0) = \dfrac{e^{- \ 0.5 }( 0.5)^ 0}{0!}](https://tex.z-dn.net/?f=P%28X%3D0%29%20%3D%20%5Cdfrac%7Be%5E%7B-%20%5C%200.5%20%7D%28%200.5%29%5E%200%7D%7B0%21%7D)
![P(X=0) = 0.60653](https://tex.z-dn.net/?f=P%28X%3D0%29%20%3D%200.60653)
P(X=0) = 0.6065
Assume the number of paints on the door by q = 10000
Hence; the number of doors that have no blemishes is = qp
=10,000(0.6065)
= 6065