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Irina-Kira [14]
3 years ago
8

4 What is the solution to the inequality -3x-42>3 ?

Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • What is the solution to the inequality -3x-42>3 ?

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

- 3 x - 42 \gt 3

Add 42 to both sides.

-3x>3+42

Add 3 and 42 to get 45.

-3x>45

Divide both sides by -3. As -3 is <0, the inequality direction has changed.

x

Divide 45 by -3 to get -15.

\huge \boxed{ \boxed{ \bf \: x

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Step-by-step explanation:

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3 years ago
Liem is 6 feet 2 inches, Eli is 5 feet 9 inches, Faith is 6 feet, and Simon is 5 feet 4 inches. In yards, what is the total of t
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4 years ago
a circles diameter matches the side length of a square. What percent of the square's area is the circle's area?
pickupchik [31]

Answer:

<h2>78.5%</h2>

Step-by-step explanation:

\text{Let}\ s\ -\ \text{side length of a square. Therefore the diameter d = 2r has }\\\text{length d=s}\to 2r=s\to r=\dfrac{s}{2}.\\r-\text{radius}\\\\\text{The formula of an area of a square:}\\\\A_{\square}=(side\ length)^2\\\\\text{Therefore:}\ A_{\square}=s^2.\\\\\text{The formula of an area of a circle:}\\\\A_O=\pi r^2\\\\\text{Substitute}\ r=\dfrac{s}{2}:\\\\A_O=\pi\left(\dfrac{s}{2}\right)^2=\dfrac{s^2\pi}{4}

\text{Calculate what fraction of the area of the square is the area of ​​the circle}\\\\\dfrac{A_O}{A_{\square}}=\dfrac{\frac{s^2\pi}{4}}{s^2}=\dfrac{s^2\pi}{4}\cdot\dfrac{1}{s^2}\qquad\text{cancel}\ s^2\\\\\dfrac{A_O}{A_{\squera}}=\dfrac{\pi}{4}\\\\\text{Convert to the percent:}\\\\\dfrac{\pi}{4}\cdot100\%=25\pi\%\\\\\pi\approx3.14\to25\pi\%\approx(25)(3.14)\%=78,5\%

3 0
3 years ago
Graph the line with slope 3 passing through the point( 2,3) .
givi [52]

Answer:

The graph is shown below.

Step-by-step explanation:

Given:

Slope of line =3

The line passes through the point (2,3)

To graph the line.

Solution:

In order to graph the line, we will first find the equation of the line.

Using point slope equation of line:

y-y_1=m(x-x_1)

where m represents slope of line and (x_1,y_1) represents the point on the line.

Plugging in the slope and the point given in the equation.

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Using distribution.

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Thus, we can graph the equation of the line.

When x=0

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Point (0,-3)

We have two points (2,3) and (0,-3) to graph the line.

5 0
3 years ago
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