All categories

3 years ago

Stoichiometry :

Chemistry

1 answer:

Yakvenalex [24]3 years ago

7 0

7.200318447 moles MgCl2

You might be interested in

thank you so much for helping me I don't know science that well trying to get better I've been getting better good grades but st

Rasek [7]

there is not enough information to make a prediction as we dont know what side she taped on magnet C

5 0

3 years ago

If you start with 512 grams of aluminum and 1147 grams of copper chloride to make aluminum chloride and copper, what is the limi

Archy [21]

First you need to calculate the number of moles of aluminium and copper chloride.

number of moles = mass / molecular weight

moles of Al = 512 / 27 = 19 moles

moles of CuCl = 1147 / 99 = 11.6 moles

From the reaction you see that:

if 2 moles of Al will react with 3 moles of CuCl

then 19 moles of Al will react with X moles of CuCl

X = (19 × 3) / 2 = 28.5 moles of CuCl, way more that 11.6 moles of CuCl wich is the quantity you have. So the copper chloride is the limiting reagent.

6 0

3 years ago

Pls help me do this and I'll give you pts and Brainliest thanks friend and anything!

Greeley [361]

Hello! Please insert your item as an image and not a document so that I may view it!!

8 0

3 years ago

Read 2 more answers

Chemosynthesis and photosynthesis are both processes that produce food. <br><br> True or false?

MA_775_DIABLO [31]

Answer:

true

Explanation:

probably true

8 0

3 years ago

Which equilibrium constant expression(s) are for the following reaction. (X stands for the mole fraction of the indicated substa

Kruka [31]

Answer : The correct alphabetical order will be, CDE

Explanation :

Equilibrium constant : It is defined as the ratio of concentration of products to the concentration of reactants. It is represented as $K$ .

The given balanced equilibrium reaction is,

$Cl_2(g)+PCl_3(g)\rightleftharpoons PCl_5(g)$

As we know that the concentrations of pure solids are constant that means they do not change. Thus, they are not included in the equilibrium expression.

The expression for equilibrium constant for this reaction will be,

$K=\frac{(p_{PCl_5})_{eq}}{(p_{Cl_2})_{eq}(p_{PCl_3})_{eq}}$

or,

$K=(p_{PCl_5})_{eq}\times (p_{Cl_2})_{eq}^{-1}\times (p_{PCl_3})_{eq}^{-1}$

From the expression of equilibrium constant we conclude that the alphabetical order will be, CDE.

Hence, the correct alphabetical order will be, CDE

6 0

3 years ago