4 years ago

How many O atoms are present in 1.04 moles of MgSO4?

1 answer:

4 0

(1.04/120.38)x(4 moles of O)x(6.022x10^23) = 2.081x10^22 O

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pav-90 [236]

Answer: 1. The average atomic mass of chlorine is 35.453u

2. The average atomic mass of copper is 63.5 u

Explanation:

Average atomic mass is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

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$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

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$\text{Average atomic mass of chlorine }=(34.9689\times \frac{75.771}{100})+(36.9659\times \frac{24.229}{100})=35.453u$

2. For copper:

$\text{Average atomic mass of chlorine }=(62.93\times \frac{69.1}{100})+(64.93\times \frac{30.9}{100})=63.5u$

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