Answer:
0.3936 J/gC
Explanation:
using the formula: q=mcΔt
q= 7032J
m=812g
ΔT = 22C
plug in and solve:
7032=(812)(c)(22)
c=7032/(812)(22)
c=0.39 J/gC
D. The nucleus is the control center of the cell
Answer:
Can you please tell us what the following are?
Answer:
The partial pressure of CO is 5.54x10⁻⁴⁹atm. You shouldn't worry because it is very low pressure
Explanation:
First, the balanced reaction is:
CO + 1/2O₂ → CO₂
The energies of formation are:
ΔG(CO)=-137.168kJ/mol
ΔG(O₂)=0
ΔG(CO₂)=-394.359kJ/mol
The energy of the reaction is:

The expression for calculate the partial pressure of CO is:
