2C⁺²O⁻² + 2N⁺²O⁻² = 2C⁺⁴O⁻²₂ + N₂⁰
C⁺² → C⁺⁴ + 2e⁻
carbon was oxidized
Answer:

Explanation:
Hello,
In this case, since nitric acid is HNO₃ and strontium hydroxide is Sr(OH)₂ we can represent the balanced chemical reaction by equaling the atoms of strontium, nitrogen, oxygen and hydrogen at both reactants and products as shown below:

Best regards.
Answer:
A
Explanation:
I believe it's A gggggg%gggggtggg
Answer:
Please find the ten balanced equations below
Explanation:
According to the question, a balanced equation must contain equal number of atoms on both sides of the equation. To balance an equation, coefficients are used. The following are the balanced equation:
1. C + O2 → CO2 (balanced)
2. 2H2 + O2 → 2H2O (balanced)
3. 2Na + 2H2O → 2NaOH + H2 (balanced)
4. 4Na + O2 → 2Na2O (balanced)
5. 2Na + Cl2 → 2NaCl (balanced)
6. NaOH + HCl → NaCl + H2O (balanced)
7. NaOH + HNO3 → NaNO3 + H2O (balanced)
8. 2NaOH + H2SO4 → Na2SO4 + 2H2O (balanced)
9. Na2CO3 + 2HCl → 2NaCl + H2O + CO2 (balanced)
10. 2NaOH + CO2 → Na2CO3 + H2O (balanced)